问题
What\'s the shorthand for inserting a new record or updating if it doesn\'t exist?
<?php
$shopOwner = ShopMeta::where(\'shopId\', \'=\', $theID)
->where(\'metadataKey\', \'=\', 2001)->first();
if ($shopOwner == null) {
// Insert new record into database
} else {
// Update the existing record
}
回答1:
Here's a full example of what "lu cip" was talking about:
$user = User::firstOrNew(array('name' => Input::get('name')));
$user->foo = Input::get('foo');
$user->save();
Below is the updated link of the docs which is on the latest version of Laravel
Docs here: Updated link
回答2:
Updated: Aug 27 2014 - [updateOrCreate Built into core...]
Just in case people are still coming across this... I found out a few weeks after writing this, that this is in fact part of Laravel's Eloquent's core...
Digging into Eloquent’s equivalent method(s). You can see here:
https://github.com/laravel/framework/blob/4.2/src/Illuminate/Database/Eloquent/Model.php#L553
on :570 and :553
/**
* Create or update a record matching the attributes, and fill it with values.
*
* @param array $attributes
* @param array $values
* @return static
*/
public static function updateOrCreate(array $attributes, array $values = array())
{
$instance = static::firstOrNew($attributes);
$instance->fill($values)->save();
return $instance;
}
Old Answer Below
I am wondering if there is any built in L4 functionality for doing this in some way such as:
$row = DB::table('table')->where('id', '=', $id)->first();
// Fancy field => data assignments here
$row->save();
I did create this method a few weeks back...
// Within a Model extends Eloquent
public static function createOrUpdate($formatted_array) {
$row = Model::find($formatted_array['id']);
if ($row === null) {
Model::create($formatted_array);
Session::flash('footer_message', "CREATED");
} else {
$row->update($formatted_array);
Session::flash('footer_message', "EXISITING");
}
$affected_row = Model::find($formatted_array['id']);
return $affected_row;
}
I Hope that helps. I would love to see an alternative to this if anyone has one to share. @erikthedev_
回答3:
As in Laravel >= 5.3, if someone is still curious how to do so in easy way. Its possible by using : updateOrCreate().
For example for asked question you can use something like:
$matchThese = array('shopId'=>$theID,'metadataKey'=>2001);
ShopMeta::updateOrCreate($matchThese,['shopOwner'=>'New One']);
Above code will check the table represented by ShopMeta, which will be most likely shop_metas unless not defined otherwise in model itself
and it will try to find entry with
column shopId = $theID
and
column metadateKey = 2001
and if it finds then it will update column shopOwner of found row to New One.
If it finds more than one matching rows then it will update the very first row that means which has lowest primary id.
If not found at all then it will insert a new row with :
shopId = $theID,metadateKey = 2001 and shopOwner = New One
Notice
Check your model for $fillable and make sue that you have every column name defined there which you want to insert or update and rest columns have either default value or its id column auto incremented one.
Otherwise it will throw error when executing above example:
Illuminate\Database\QueryException with message 'SQLSTATE[HY000]: General error: 1364 Field '...' doesn't have a default value (SQL: insert into `...` (`...`,.., `updated_at`, `created_at`) values (...,.., xxxx-xx-xx xx:xx:xx, xxxx-xx-xx xx:xx:xx))'
As there would be some field which will need value while inserting new row and it will not be possible as either its not defined in $fillable or it doesnt have default value.
For more reference please see Laravel Documentation at : https://laravel.com/docs/5.3/eloquent
One example from there is:
// If there's a flight from Oakland to San Diego, set the price to $99.
// If no matching model exists, create one.
$flight = App\Flight::updateOrCreate(
['departure' => 'Oakland', 'destination' => 'San Diego'],
['price' => 99]
);
which pretty much clears everything.
Query Builder Update
Someone has asked if it is possible using Query Builder in Laravel. Here is reference for Query Builder from Laravel docs.
Query Builder works exactly the same as Eloquent so anything which is true for Eloquent is true for Query Builder as well. So for this specific case, just use the same function with your query builder like so:
$matchThese = array('shopId'=>$theID,'metadataKey'=>2001);
DB::table('shop_metas')::updateOrCreate($matchThese,['shopOwner'=>'New One']);
Of course, don't forget to add DB facade:
use Illuminate\Support\Facades\DB;
OR
use DB;
I hope it helps
回答4:
Save function:
$shopOwner->save()
already do what you want...
Laravel code:
// If the model already exists in the database we can just update our record
// that is already in this database using the current IDs in this "where"
// clause to only update this model. Otherwise, we'll just insert them.
if ($this->exists)
{
$saved = $this->performUpdate($query);
}
// If the model is brand new, we'll insert it into our database and set the
// ID attribute on the model to the value of the newly inserted row's ID
// which is typically an auto-increment value managed by the database.
else
{
$saved = $this->performInsert($query);
}
回答5:
firstOrNew will create record if not exist and updating a row if already exist.
You can also use updateOrCreate here is the full example
$flight = App\Flight::updateOrCreate(
['departure' => 'Oakland', 'destination' => 'San Diego'],
['price' => 99]
);
If there's a flight from Oakland to San Diego, set the price to $99. if not exist create new row
Reference Doc here: (https://laravel.com/docs/5.5/eloquent)
回答6:
$shopOwner = ShopMeta::firstOrNew(array('shopId' => $theID,'metadataKey' => 2001));
Then make your changes and save. Note the firstOrNew doesn't do the insert if its not found, if you do need that then its firstOrCreate.
回答7:
If you need the same functionality using the DB, in Laravel >= 5.5 you can use:
DB::table('table_name')->updateOrInsert($attributes, $values);
or the shorthand version when $attributes and $values are the same:
DB::table('table_name')->updateOrInsert($values);
回答8:
One more option if your id isn't autoincrement and you know which one to insert/update:
$object = MyModel::findOrNew($id);
//assign attributes to update...
$object->save();
回答9:
Actually firstOrCreate would not update in case that the register already exists in the DB. I improved a bit Erik's solution as I actually needed to update a table that has unique values not only for the column "id"
/**
* If the register exists in the table, it updates it.
* Otherwise it creates it
* @param array $data Data to Insert/Update
* @param array $keys Keys to check for in the table
* @return Object
*/
static function createOrUpdate($data, $keys) {
$record = self::where($keys)->first();
if (is_null($record)) {
return self::create($data);
} else {
return self::where($keys)->update($data);
}
}
Then you'd use it like this:
Model::createOrUpdate(
array(
'id_a' => 1,
'foo' => 'bar'
), array(
'id_a' => 1
)
);
回答10:
like @JuanchoRamone posted above (thank @Juancho) it's very useful for me, but if your data is array you should modify a little like this:
public static function createOrUpdate($data, $keys) {
$record = self::where($keys)->first();
if (is_null($record)) {
return self::create($data);
} else {
return $record->update($data);
}
}
回答11:
Like the firstOrCreate method, updateOrCreate persists the model, so there's no need to call save()
// If there's a flight from Oakland to San Diego, set the price to $99.
// If no matching model exists, create one.
$flight = App\Flight::updateOrCreate(
['departure' => 'Oakland', 'destination' => 'San Diego'],
['price' => 99]
);
And for your issue
$shopOwner = ShopMeta::updateOrCreate(
['shopId' => $theID, 'metadataKey' => '2001'],
['other field' => 'val' ,'other field' => 'val', ....]
);
回答12:
Isn't this the same as updateOrCreate()?
It is similar but not the same. The updateOrCreate() will only work for one row at a time which doesn't allow bulk insert. InsertOnDuplicateKey will work on many rows.
https://github.com/yadakhov/insert-on-duplicate-key
回答13:
check if a user exists or not. If not insert
$exist = DB::table('User')->where(['username'=>$username,'password'=>$password])->get();
if(count($exist) >0) {
echo "User already exist";;
}
else {
$data=array('username'=>$username,'password'=>$password);
DB::table('User')->insert($data);
}
Laravel 5.4
来源：https://stackoverflow.com/questions/18839941/creating-and-update-laravel-eloquent