问题
Using the job-dsl-plugin I am attempting to script the configuration of a fair number of Jenkins jobs which have previously been configured manually.
One flavour of these jobs has multiple steps including a couple which use the XShell plugin, this is not directly supported by job-dsl. However I should be able to get around that by using a custom "configure" block.
Using the "Job DSL playground" at http://job-dsl.herokuapp.com/ I've got as far as:
job {
name 'my-job'
jdk('JDK-17')
steps {
configure { node ->
node / builders {
'hudson.plugins.xshell.XShellBuilder'(plugin: 'xshell@0.9') {
commandLine('run-me-as-the-first-build-step')
executeFromWorkingDir('true')
}
}
}
maven {
mavenInstallation('Default')
goals('clean')
goals('verify')
property('prop1', 'value1')
property('user.timezone', 'UTC')
mavenOpts('--batch-mode')
}
maven {
mavenInstallation('Default')
goals('deploy')
property('prop2', 'value2')
property('user.timezone', 'UTC')
mavenOpts('--batch-mode')
}
shell('shell-task')
configure { node ->
node / builders {
'hudson.plugins.xshell.XShellBuilder'(plugin: 'xshell@0.9') {
commandLine('run-me-as-the-last-build-step')
executeFromWorkingDir('true')
}
}
}
}
}
If I just include the first configure block only, I do get the first command at the first step position. But with the second (last) configure block present, the "node / builders"
is matching on the first element again and overwriting it, so run-me-as-the-last-step
is the first and only XShellBuilder. The output I seek would look something like:
<project>
...
<builders>
<hudson.plugins.xshell.XShellBuilder plugin='xshell@0.9'>
<commandLine>run-me-as-the-first-build-step</commandLine>
<executeFromWorkingDir>true</executeFromWorkingDir>
</hudson.plugins.xshell.XShellBuilder>
<hudson.tasks.Maven>
<targets>clean verify</targets>
<properties>prop1=value1
user.timezone=UTC</properties>
<mavenName>Default</mavenName>
<jvmOptions>--batch-mode</jvmOptions>
<usePrivateRepository>false</usePrivateRepository>
</hudson.tasks.Maven>
<hudson.tasks.Maven>
<targets>deploy</targets>
<properties>prop2=value2
user.timezone=UTC</properties>
<mavenName>Default</mavenName>
<jvmOptions>--batch-mode</jvmOptions>
<usePrivateRepository>false</usePrivateRepository>
</hudson.tasks.Maven>
<hudson.tasks.Shell>
<command>shell-task</command>
</hudson.tasks.Shell>
<hudson.plugins.xshell.XShellBuilder plugin='xshell@0.9'>
<commandLine>run-me-as-the-last-build-step</commandLine>
<executeFromWorkingDir>true</executeFromWorkingDir>
</hudson.plugins.xshell.XShellBuilder>
</builders>
...
</project>
I can't figure out the Groovy XML / Job-DSL syntax to insert that second block as "last child; can a Job-DSL or Groovy XMLParser expert please give me a pointer on how to match and insert at an arbitrary position in the children of <builders>
?
(I appreciate that I could use job(type:Maven)
with preBuildSteps
and postBuildSteps
but actually I need a few other things in there as well which a pure maven job precludes.)
Thanks!
回答1:
You can use the <<
operator to append nodes, otherwise an existing node with an identical name gets replaced. See the Job DSL wiki for details.
job {
name('foo')
steps {
shell('echo AAA')
}
configure {
it / builders << 'hudson.plugins.xshell.XShellBuilder' {
commandLine('123')
}
}
steps {
shell('echo BBB')
}
configure {
it / builders << 'hudson.plugins.xshell.XShellBuilder' {
commandLine('456')
}
}
}
来源:https://stackoverflow.com/questions/28548472/using-jenkins-job-dsl-configure-block-to-place-custom-steps-in-particular-positi