Convert NetCDF file to CSV or text using Python

纵饮孤独 提交于 2019-11-29 08:58:37

I think pandas.Series should work for you to create a CSV with time, lat,lon,precip.

import netCDF4
import pandas as pd

precip_nc_file = 'file_path'
nc = netCDF4.Dataset(precip_nc_file, mode='r')

nc.variables.keys()

lat = nc.variables['lat'][:]
lon = nc.variables['lon'][:]
time_var = nc.variables['time']
dtime = netCDF4.num2date(time_var[:],time_var.units)
precip = nc.variables['precip'][:]

# a pandas.Series designed for time series of a 2D lat,lon grid
precip_ts = pd.Series(precip, index=dtime) 

precip_ts.to_csv('precip.csv',index=True, header=True)

Depending on your requirements, you may be able to use Numpy's savetxt method:

import numpy as np

np.savetxt('lat.csv', lat, delimiter=',')
np.savetxt('lon.csv', lon, delimiter=',')
np.savetxt('precip.csv', precip, delimiter=',')

This will output the data without any headings or index column, however.

If you do need those features, you can construct a DataFrame and save it as CSV as follows:

df_lat = pd.DataFrame(data=lat, index=dtime)
df_lat.to_csv('lat.csv')

# and the same for `lon` and `precip`.

Note: here, I assume that the date/time index runs along the first dimension of the data.

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