Is there a regex flavor that allows me to count the number of repetitions matched by the * and + operators?

倖福魔咒の 提交于 2019-11-26 08:37:31

问题


Is there a regex flavor that allows me to count the number of repetitions matched by the * and + operators? I\'d specifically like to know if it\'s possible under the .NET Platform.


回答1:


You're fortunate because in fact .NET regex does this (which I think is quite unique). Essentially in every Match, each Group stores every Captures that was made.

So you can count how many times a repeatable pattern matched an input by:

  • Making it a capturing group
  • Counting how many captures were made by that group in each match
    • You can iterate through individual capture too if you want!

Here's an example:

Regex r = new Regex(@"\b(hu?a)+\b");

var text = "hahahaha that's funny but not huahuahua more like huahahahuaha";
foreach (Match m in r.Matches(text)) {
   Console.WriteLine(m + " " + m.Groups[1].Captures.Count);
}

This prints (as seen on ideone.com):

hahahaha 4
huahuahua 3
huahahahuaha 5

API references

  • CaptureCollection



回答2:


You can use parentheses in the expression to create a group and then use the + or * operator on the group. The Captures property of the Group can be used to determine how many times it was matched. The following example counts the number of consecutive lower-case letters at the start of a string:

var regex = new Regex(@"^([a-z])+");
var match = regex.Match("abc def");

if (match.Success)
{
    Console.WriteLine(match.Groups[1].Captures.Count);
}



回答3:


how about taking "pref ([a-z]+) suff"

then use groups to capture that [a-z]+ in the bracket and find its length?

You can use this length for subsequent matching as well.



来源:https://stackoverflow.com/questions/3029127/is-there-a-regex-flavor-that-allows-me-to-count-the-number-of-repetitions-matche

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