Scala convert List[Int] to a java.util.List[java.lang.Integer]

问题

Is there a way in Scala to convert a List[Int] to java.util.List[java.lang.Integer]?

I'm interfacing with Java (Thrift).

JavaConversions supports List --> java.util.List, and implicits exist between Int --> java.lang.Integer, but from what I can tell I would still need an extra pass to manually do the conversion:

val y = List(1)     
val z: java.util.List[Integer] = asList(y)  map { (x: Int) => x : java.lang.Integer }

回答1:

Apparently you need both conversions. However, you can group them in a single implicit conversion:

implicit def toIntegerList( lst: List[Int] ) =
  seqAsJavaList( lst.map( i => i:java.lang.Integer ) )

Example:

scala> def sizeOf( lst: java.util.List[java.lang.Integer] ) = lst.size

scala> sizeOf( List(1,2,3) )
res5: Int = 3

回答2:

Because the underlying representation of Int is Integer you can cast directly to java.util.List[java.lang.Integer]. It will save you an O(n) operation and some implicit stuff.

import collection.JavaConversions._

class A {
  def l() = asList(List(1,2)).asInstanceOf[java.util.List[java.lang.Integer]]
}

Then you can use from Java like this:

A a = new A();
java.util.List<Integer> l = a.l();

Note that on 2.9.0 ,I get a deprecation warning on asList (use seqAsJavaList instead)

回答3:

Did you try:

val javalist = collection.JavaConversions.asJavaList (y)

I'm not sure, whether you need a conversion Int=>Integer or Int=>int here. Can you try it out?

Update: The times, they are a changing. Today you'll get a deprecated warning for that code. Use instead:

import scala.collection.JavaConverters._
val y = List (1)
> y: List[Int] = List(1)

val javalist = (y).asJava
> javalist: java.util.List[Int] = [1]

回答4:

This doesn't have an implicit at the outmost layer, but I like this generic approach and have implemented it for a couple of types of collections (List, Map).

import java.util.{List => JList}
import scala.collection.JavaConverters._

  def scalaList2JavaList[A, B](scalaList: List[A])
                              (implicit a2bConversion: A => B): JList[B] =
    (scalaList map a2bConversion).asJava

Since an implicit conversion from Int to Integer is part of standard lib, usage in this case would just look like this:

  scalaList2JavaList[Int, Integer](someScalaList)

In the other direction!

(since I have these available anyway as they were my original implementations...)

import java.util.{List => JList}
import scala.collection.JavaConversions._

  def javaList2ScalaList[A, B](javaList: JList[A])
                              (implicit a2bConversion: A => B): List[B] =
    javaList.toList map a2bConversion

Usage:

  javaList2ScalaList[Integer, Int](someJavaList)

This can then be re-used for all lists so long as an implicit conversion of the contained type is in scope.

(And in case you're curious, here is my implementation for map...)

  def javaMap2ScalaMap[A, B, C, D](javaMap: util.Map[A, B])(implicit a2cConversion: A => C, b2dConversion: B => D): Map[C, D] =
    javaMap.toMap map { case (a, b) => (a2cConversion(a), b2dConversion(b)) }

回答5:

I was trying to pass a Map[String, Double] to a Java method. But the problem was JavaConversions converts the Map to a java Map, but leaves the scala Double as is, instead of converting it to java.lang.Double. After a few hours of seaching I found [Alvaro Carrasco's answer])https://stackoverflow.com/a/40683561/1612432), it is as simple as doing:

val scalaMap = // Some Map[String, Double]
val javaMap = scalaMap.mapValues(Double.box)

After this, javaMap is a Map[String, java.lang.Double]. Then you can pass this to a java function that expects a Map<String, Double> and thanks to implicit conversions the Scala Map will be converted to java.util.Map

In your case would be the same, but with Int.box:

val y = List(1)
val javay = y.map(Int.box)

回答6:

Starting Scala 2.13, the standard library includes scala.jdk.CollectionConverters which provides Scala to Java implicit collection conversions.

Which we can combine with java.lang.Integer::valueOf to convert Scala's Int to Java's Integer:

import scala.jdk.CollectionConverters._

List(1, 2, 3).map(Integer.valueOf).asJava
// java.util.List[Integer] = [1, 2, 3]

来源：https://stackoverflow.com/questions/6991340/scala-convert-listint-to-a-java-util-listjava-lang-integer

标签

scala

scala-java-interop