Change the volume of a wav file in python

问题

I have a 2 seconds 16bit single channel 8khz wav file and I need to change its volume.

It should be quite straightforward, because changing the volume is the same as changing the amplitude of the signal, and I just need to attenuate it, that is to multiply it for a number between 0 and 1. But it doesn't work: the new sound is lower but VERY full of noise. What am I doing wrong?

Here is my code:

import wave, numpy, struct

# Open
w = wave.open("input.wav","rb")
p = w.getparams()
f = p[3] # number of frames
s = w.readframes(f)
w.close()

# Edit
s = numpy.fromstring(s, numpy.int16) * 5 / 10  # half amplitude
s = struct.pack('h'*len(s), *s)

# Save
w = wave.open("output.wav","wb")
w.setparams(p)
w.writeframes(s)
w.close()

Thank you guys!

回答1:

I wrote a library to simplify this type of thing

You can do that like so:

from pydub import AudioSegment

song = AudioSegment.from_wav("never_gonna_give_you_up.wav")

# reduce volume by 10 dB
song_10_db_quieter = song - 10

# but let's make him *very* quiet
song = song - 36

# save the output
song.export("quieter.wav", "wav")

回答2:

As you can see in the comments of the question, there are several solutions, some more efficient.

The problem was immediately detected by Jan Dvorak ("the * 5 part is clipping and overflowing") and the straightforward solution was:

s = numpy.fromstring(s, numpy.int16) / 10 * 5

In this case, this solution was perfect for me, just good enough.

Thank you all folks!

来源：https://stackoverflow.com/questions/13329617/change-the-volume-of-a-wav-file-in-python