测试下java函数式编程的几个接口

//看着很简洁，就是有点难理解

public class Iterator_test {

public static void main(String[] args) {

    List<String> list=new ArrayList<>();
	
    list.add("343");
    list.add("343434");
	
    //使用Consumer接口
    //函数式编程,消费者
    list.forEach((String s)-> {System.out.println(s);});
    list.forEach(s->System.out.println(s));
    list.forEach(System.out::println);

    //使用Function接口
    String s=Function_test("hello word",(s1)->s1+" wind");
    String s2=Function_test("hello word",(s1)->{String a=s1+" hi";return a;});
    System.out.println(s);
    System.out.println(s2);

    //测试supplier接口
    List<Integer> mao=Supplier_test(5,()->(int)(Math.random()*10));
    mao.forEach(System.out::println);

    //测试下断言接口predicate
    List<String> list1= Arrays.asList("hello","wored","english","china");
    List<String> list2=predicte(list1,(ss)->ss.contains("o"));
    list2.forEach(System.out::println);
}

public static String Function_test(String str, Function<String,String> f){
    return f.apply(str);
}

public static List<Integer> Supplier_test(int n, Supplier<Integer> s){ List<Integer> list =new ArrayList<>(); for(int i=0;i<n;i++) list.add(s.get()); return list; }

public static List<String> predicte(List<String> list, Predicate<String> p){ List<String> re=new ArrayList<>(); for (String s:list) if(p.test(s)) re.add(s); return re; } }

来源：https://my.oschina.net/u/2511906/blog/3100409