问题
How can I find duration of a video file in miliseconds i.e. in integer in deterministic way. I have used ffprobe to get the duration but it doesn't give duration for all file formats.
回答1:
Use the following commands:
i) To get the duration of video stream:
$ mediainfo --Inform="Video;%Duration%" [inputfile]
ii) To get the duration of the media file:
$ mediainfo --Inform="General;%Duration%" [inputfile]
iii) To get the duration of audio stream only:
$ mediainfo --Inform="Audio;%Duration%" [inputfile]
iv) To get values of more than one parameter:
$ mediainfo --Inform="Video;%Width%,%Height%,%BitRate%,%FrameRate%" [inputfile]
Output would be something like this:
1280,720,3000000,30.0
回答2:
As offered by iota to use mediainfo --Inform="Video;%Duration%" [inputfile], possible but returns weird results.
For example, for video with duration 31s 565ms the output of given command would be:
31565
It wasn't suitable for me and I came up to the following solution:
mediainfo --Inform="Video;%Duration/String3%" inputExample.webm
Returned value is:
00:00:31.565
After all, you could just format returned value with, let's say PHP, to convert it to seconds, e.g.:
$parsed = date_parse( '00:00:31.565' );
echo $parsed['hour'] * 3600 + $parsed['minute'] * 60 + $parsed['second'];
Example
回答3:
we can also use ffmpeg to get the duration of any video or audio files.
To install ffmpeg follow this link
import subprocess
import re
process = subprocess.Popen(['ffmpeg', '-i', path_of_media_file], stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
stdout, stderr = process.communicate()
matches = re.search(r"Duration:\s{1}(?P<hours>\d+?):(?P<minutes>\d+?):(?P<seconds>\d+\.\d+?),", stdout, re.DOTALL).groupdict()
print matches['hours']
print matches['minutes']
print matches['seconds']
来源：https://stackoverflow.com/questions/19091771/how-to-find-duration-of-a-video-file-using-mediainfo-in-seconds-or-other-formats