PHP — Convert milliseconds to Hours : Minutes : Seconds.fractional

Question

I've got a script that takes in a value in seconds (to 2 decimal points of fractional seconds):

$seconds_input = 23.75

I then convert it to milliseconds:

$milliseconds = $seconds_input * 1000; // --> 23750

And then I want to format it like so:

H:M:S.x // --> 0:0:23.75

Where 'x' is the fraction of the second (however many places after the decimal there are).

Any help? I can't seem to wrap my mind around this. I tried using gmdate() but it kept lopping off the fractional seconds.

Thanks.

Answer 1

My take

function formatSeconds( $seconds )
{
  $hours = 0;
  $milliseconds = str_replace( "0.", '', $seconds - floor( $seconds ) );

  if ( $seconds > 3600 )
  {
    $hours = floor( $seconds / 3600 );
  }
  $seconds = $seconds % 3600;


  return str_pad( $hours, 2, '0', STR_PAD_LEFT )
       . gmdate( ':i:s', $seconds )
       . ($milliseconds ? ".$milliseconds" : '')
  ;
}

And then the test

$testData = array(
    23,              // Seconds, w/o millis
    23.75,           // Seconds, w/millis
    23.75123456789,  // Lots of millis
    123456789.75    // Lots of seconds
);

foreach ( $testData as $seconds )
{
  echo formatSeconds( $seconds ), PHP_EOL;
}

which yields

00:00:23
00:00:23.75
00:00:23.75123456789
34293:33:09.75

Answer 2

Edit: Well, I was a bit hasty. Here's one way to do what you're asking:

function formatMilliseconds($milliseconds) {
    $seconds = floor($milliseconds / 1000);
    $minutes = floor($seconds / 60);
    $hours = floor($minutes / 60);
    $milliseconds = $milliseconds % 1000;
    $seconds = $seconds % 60;
    $minutes = $minutes % 60;

    $format = '%u:%02u:%02u.%03u';
    $time = sprintf($format, $hours, $minutes, $seconds, $milliseconds);
    return rtrim($time, '0');
}

Answer 3

Mine is much less readable, so it must be better. :p

Basically the same idea as @ircmaxell's version. It does trim the trailing '0's and even will skip the last '.' separator if milliseconds are 0.

<?

function format_period($seconds_input)
{
  $hours = (int)($minutes = (int)($seconds = (int)($milliseconds = (int)($seconds_input * 1000)) / 1000) / 60) / 60;
  return $hours.':'.($minutes%60).':'.($seconds%60).(($milliseconds===0)?'':'.'.rtrim($milliseconds%1000, '0'));
}

echo format_period(23.75);

Answer 4

if you really want to do it using date function you are right, you have to deal with milliseconds externally, is only based on second-timestamps.

you could do something like this:

<?
$input = "23.75";
$seconds = floor($input);
$date = DateTime::createFromFormat('s', floor($seconds));
$ms = ($input-$seconds);
if($ms == 0) {
$ms = "";
} else { 
$ms = ltrim($ms,"0,");
}
echo $date->format('H:i:s').$ms;

but be aware of the hour-overflow, if your hours exceed 24 you will probably end up discarding the days.

in your case i would say your approach with floor to get the seconds is correct, and then you should probably just use modulo arithmetics like this:

<?
$totalsecs = 86400*10;

$secs = $totalsecs%60;

echo "secs: $secs \n";

$minutes = ($totalsecs - $secs) % (60*60);

?> and so on..