Best way to check that element is not present using Selenium WebDriver with java

问题

Im trying the code below but it seems it does not work... Can someone show me the best way to do this?

public void verifyThatCommentDeleted(final String text) throws Exception {
    new WebDriverWait(driver, 5).until(new ExpectedCondition<Boolean>() {
            @Override
            public Boolean apply(WebDriver input) {
                try {
                    input.findElement(By.xpath(String.format(
                            Locators.CHECK_TEXT_IN_FIRST_STATUS_BOX, text)));
                    return false;
                } catch (NoSuchElementException e) {
                    return true;
                }
            }
        });
    }

回答1:

i usually couple of methods (in pair) for verification whether element is present or not:

public boolean isElementPresent(By locatorKey) {
    try {
        driver.findElement(locatorKey);
        return true;
    } catch (org.openqa.selenium.NoSuchElementException e) {
        return false;
    }
}

public boolean isElementVisible(String cssLocator){
    return driver.findElement(By.cssSelector(cssLocator)).isDisplayed();
}

Note that sometimes selenium can find elements in DOM but they can be invisible, consequently selenium will not be able to interact with them. So in this case method checking for visibility helps.

If you want to wait for the element until it appears the best solution i found is to use fluent wait:

public WebElement fluentWait(final By locator){
    Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
            .withTimeout(30, TimeUnit.SECONDS)
            .pollingEvery(5, TimeUnit.SECONDS)
            .ignoring(NoSuchElementException.class);

    WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
        public WebElement apply(WebDriver driver) {
            return driver.findElement(locator);
        }
    });

    return foo;
};

Hope this helps)

回答2:

Instead of doing findElement, do findElements and check the length of the returned elements is 0. This is how I'm doing using WebdriverJS and I expect the same will work in Java

回答3:

Use findElements instead of findElement.

findElements will return an empty list if no matching elements are found instead of an exception. Also, we can make sure that the element is present or not.

Ex: List elements = driver.findElements(By.yourlocatorstrategy);

if(elements.size()>0){
    do this..
 } else {
    do that..
 }

回答4:

Unable to comment to The Meteor Test Manual, since I have no rep, but I wanted to provide an example that took me quite awhile to figure out:

Assert.assertEquals(0, wd.findElements(By.locator("locator")).size());

This assertion verifies that there are no matching elements in the DOM and returns the value of Zero, so the assertion passes when the element is not present. Also it would fail if it was present.

回答5:

int i=1;

while (true) {
  WebElementdisplay=driver.findElement(By.id("__bar"+i+"-btnGo"));
  System.out.println(display);

  if (display.isDisplayed()==true)
  { 
    System.out.println("inside if statement"+i);
    driver.findElement(By.id("__bar"+i+"-btnGo")).click();
    break;
  }
  else
  {
    System.out.println("inside else statement"+ i);
    i=i+1;
  }
}

回答6:

WebElement element = driver.findElement(locator);
Assert.assertNull(element);

The above assertion will pass if element is not present.

回答7:

    WebElement element = driver.findElement(locator);

    Assert.assertFalse(element.isDisplayed());

The assertion will pass if the element is not present, otherwise it will fail.

来源：https://stackoverflow.com/questions/12270092/best-way-to-check-that-element-is-not-present-using-selenium-webdriver-with-java

标签

java

selenium-webdriver

assertion

verify