问题
What\'s a fast way to sort a given set of images by their similarity to each other.
At the moment I have a system that does histogram analysis between two images, but this is a very expensive operation and seems too overkill.
Optimally I am looking for a algorithm that would give each image a score (for example a integer score, such as the RGB Average) and I can just sort by that score. Identical Scores or scores next to each other are possible duplicates.
0299393
0599483
0499994 <- possible dupe
0499999 <- possible dupe
1002039
4995994
6004994
RGB Average per image sucks, is there something similar?
回答1:
There has been a lot of research on image searching and similarity measures. It's not an easy problem. In general, a single int won't be enough to determine if images are very similar. You'll have a high false-positive rate.
However, since there has been a lot of research done, you might take a look at some of it. For example, this paper (PDF) gives a compact image fingerprinting algorithm that is suitable for finding duplicate images quickly and without storing much data. It seems like this is the right approach if you want something robust.
If you're looking for something simpler, but definitely more ad-hoc, this SO question has a few decent ideas.
回答2:
I would recommend considering moving away from just using an RGB histogram.
A better digest of your image can be obtained if you take a 2d Haar wavelet of the image (its a lot easier than it sounds, its just a lot of averaging and some square roots used to weight your coefficients) and just retain the k largest weighted coefficients in the wavelet as a sparse vector, normalize it, and save that to reduce its size. You should rescale R G and B using perceptual weights beforehand at least or I'd recommend switching to YIQ (or YCoCg, to avoid quantization noise) so you can sample chrominance information with reduced importance.
You can now use the dot product of two of these sparse normalized vectors as a measure of similarity. The image pairs with the largest dot products are going to be very similar in structure. This has the benefit of being slightly resistant to resizing, hue shifting and watermarking, and being really easy to implement and compact.
You can trade off storage and accuracy by increasing or decreasing k.
Sorting by a single numeric score is going to be intractable for this sort of classification problem. If you think about it it would require images to only be able to 'change' along one axis, but they don't. This is why you need a vector of features. In the Haar wavelet case its approximately where the sharpest discontinuities in the image occur. You can compute a distance between images pairwise, but since all you have is a distance metric a linear ordering has no way to express a 'triangle' of 3 images that are all equally distant. (i.e. think of an image that is all green, an image that is all red and an image that is all blue.)
That means that any real solution to your problem will need O(n^2) operations in the number of images you have. Whereas if it had been possible to linearize the measure, you could require just O(n log n), or O(n) if the measure was suitable for, say, a radix sort. That said, you don't need to spend O(n^2) since in practice you don't need to sift through the whole set, you just need to find the stuff thats nearer than some threshold. So by applying one of several techniques to partition your sparse vector space you can obtain much faster asymptotics for the 'finding me k of the images that are more similar than a given threshold' problem than naively comparing every image against every image, giving you what you likely need... if not precisely what you asked for.
In any event, I used this a few years ago to good effect personally when trying to minimize the number of different textures I was storing, but there has also been a lot of research noise in this space showing its efficacy (and in this case comparing it to a more sophisticated form of histogram classification):
http://www.cs.princeton.edu/cass/papers/spam_ceas07.pdf
If you need better accuracy in detection, the minHash and tf-idf algorithms can be used with the Haar wavelet (or the histogram) to deal with edits more robustly:
http://cmp.felk.cvut.cz/~chum/papers/chum_bmvc08.pdf
Finally, Stanford has an image search based on a more exotic variant of this kind of approach, based on doing more feature extraction from the wavelets to find rotated or scaled sections of images, etc, but that probably goes way beyond the amount of work you'd want to do.
http://wang14.ist.psu.edu/cgi-bin/zwang/regionsearch_show.cgi
回答3:
I implemented a very reliable algorithm for this called Fast Multiresolution Image Querying. My (ancient, unmaintained) code for that is here.
What Fast Multiresolution Image Querying does is split the image into 3 pieces based on the YIQ colorspace (better for matching differences than RGB). Then the image is essentially compressed using a wavelet algorithm until only the most prominent features from each colorspace are available. These points are stored in a data structure. Query images go through the same process, and the prominent features in the query image are matched against those in the stored database. The more matches, the more likely the images are similar.
The algorithm is often used for "query by sketch" functionality. My software only allowed entering query images via URL, so there was no user interface. However, I found it worked exceptionally well for matching thumbnails to the large version of that image.
Much more impressive than my software is retrievr which lets you try out the FMIQ algorithm using Flickr images as the source. Very cool! Try it out via sketch or using a source image, and you can see how well it works.
回答4:
A picture has many features, so unless you narrow yourself to one, like average brightness, you are dealing with an n-dimensional problem space.
If I asked you to assign a single integer to the cities of the world, so I could tell which ones are close, the results wouldn't be great. You might, for example, choose time zone as your single integer and get good results with certain cities. However, a city near the north pole and another city near the south pole can also be in the same time zone, even though they are at opposite ends of the planet. If I let you use two integers, you could get very good results with latitude and longitude. The problem is the same for image similarity.
All that said, there are algorithms that try to cluster similar images together, which is effectively what you're asking for. This is what happens when you do face detection with Picasa. Even before you identify any faces, it clusters similar ones together so that it's easy to go through a set of similar faces and give most of them the same name.
There is also a technique called Principle Component Analysis, which lets you reduce n-dimensional data down to any smaller number of dimensions. So a picture with n features could be reduced to one feature. However, this is still not the best approach for comparing images.
回答5:
There's a C library ("libphash" - http://phash.org/) that will calculate a "perceptual hash" of an image and allow you to detect similar images by comparing hashes (so you don't have to compare each image directly against every other image) but unfortunately it didn't seem to be very accurate when I tried it.
回答6:
You have to decide what is "similar." Contrast? Hue?
Is a picture "similar" to the same picture upside-down?
I bet you can find a lot of "close calls" by breaking images up into 4x4 pieces and getting an average color for each grid cell. You'd have sixteen scores per image. To judge similarity, you would just do a sum of squares of differences between images.
I don't think a single hash makes sense, unless it's against a single concept like hue, or brightness, or contrast.
Here's your idea:
0299393
0599483
0499994 <- possible dupe
0499999 <- possible dupe
1002039
4995994
6004994
First of all, I'm going to assume these are decimal numbers that are R*(2^16)+G*(2^8)+B, or something like that. Obviously that's no good because red is weighted inordinately.
Moving into HSV space would be better. You could spread the bits of HSV out into the hash, or you could just settle H or S or V individually, or you could have three hashes per image.
One more thing. If you do weight R, G, and B. Weight green highest, then red, then blue to match human visual sensitivity.
回答7:
In the age of web services you could try http://tineye.com
回答8:
The question Good way to identify similar images? seems to provide a solution for your question.
回答9:
i assumed that other duplicate image search software performs an FFT on the images, and stores the values of the different frequencies as a vectors:
Image1 = (u1, u2, u3, ..., un)
Image2 = (v1, v2, v3, ..., vn)
and then you can compare two images for equalness by computing the distance between the weight vectors of two images:
distance = Sqrt(
(u1-v1)^2 +
(u2-v2)^2 +
(u2-v3)^2 +
...
(un-vn)^2);
回答10:
One solution is to perform a RMS/RSS comparison on every pair of pictures required to perform a bubble sort. Second, you could perform an FFT on each image and do some axis averaging to retrieve a single integer for each image which you would use as an index to sort by. You may consider doing whatever comparison on a resized (25%, 10%) version of the original depending on how small a difference you choose to ignore and how much speedup you require. Let me know if these solutions are interesting, and we can discuss or I can provide sample code.
回答11:
Most modern approaches to detect Near duplicate image detection use interesting points detection and descriptors describing area around such points. Often SIFT is used. Then you can quatize descriptors and use clusters as visual word vocabulary.
So if we see on ratio of common visual words of two images to all visual words of these images you estimate similarity between images. There are a lot of interesting articles. One of them is Near Duplicate Image Detection: minHash and tf-idf Weighting
回答12:
For example using IMMI extension and IMMI you can examine many different ways how to measure similarity between images: http://spl.utko.feec.vutbr.cz/en/component/content/article/46-image-processing-extension-for-rapidminer-5
By defining some threshold and selecting some method you can measure similarity.
来源：https://stackoverflow.com/questions/1034900/near-duplicate-image-detection