How to use SequenceMatcher to find similarity between two strings?

问题

import difflib

a='abcd'
b='ab123'
seq=difflib.SequenceMatcher(a=a.lower(),b=b.lower())
seq=difflib.SequenceMatcher(a,b)
d=seq.ratio()*100
print d

I used the above code but obtained output is 0.0. How can I get a valid answer?

回答1:

You forgot the first parameter to SequenceMatcher.

>>> import difflib
>>> 
>>> a='abcd'
>>> b='ab123'
>>> seq=difflib.SequenceMatcher(None, a,b)
>>> d=seq.ratio()*100
>>> print d
44.4444444444

http://docs.python.org/library/difflib.html

回答2:

From the docs:

The SequenceMatcher class has this constructor:

class difflib.SequenceMatcher(isjunk=None, a='', b='', autojunk=True)

The problem in your code is that by doing

seq=difflib.SequenceMatcher(a,b)

you are passing a as value for isjunk and b as value for a, leaving the default '' value for b. This results in a ratio of 0.0.

One way to overcome this (already mentioned by Lennart) is to explicitly pass None as extra first parameter so all the keyword arguments get assigned the correct values.

However I just found, and wanted to mention another solution, that doesn't touch the isjunk argument but uses the set_seqs() method to specify the different sequences.

>>> import difflib
>>> a = 'abcd'
>>> b = 'ab123'
>>> seq = difflib.SequenceMatcher()
>>> seq.set_seqs(a.lower(), b.lower())
>>> d = seq.ratio()*100
>>> print d
44.44444444444444

来源：https://stackoverflow.com/questions/4802137/how-to-use-sequencematcher-to-find-similarity-between-two-strings