问题
I have a data.frame df with 600+ variables. I'm writing a function that automates the creation of columns and need to visually check them once.
The str function provides a good summary:
str(df)
'data.frame': 29 obs. of 602 variables:
$ uniqueSessionsIni: POSIXct, format: "2015-01-05 15:00:00" "2015-01-05 16:00:00" "2015-01-05 17:00:00" ...
$ uniqueSessionsEnd: POSIXct, format: "2015-01-05 15:59:00" "2015-01-05 16:59:00" "2015-01-05 17:59:00" ...
$ m0p0 : POSIXct, format: "2015-01-05 15:00:00" "2015-01-05 15:00:00" "2015-01-05 15:00:00" ...
$ m1p0 : POSIXct, format: "2015-01-05 15:01:00" "2015-01-05 15:01:00" "2015-01-05 15:01:00" ...
$ m2p0 : POSIXct, format: "2015-01-05 15:02:00" "2015-01-05 15:02:00" "2015-01-05 15:02:00" ...
and it goes on...
but truncates the output, as below:
$ m33p1 : POSIXct, format: "2015-01-05 15:34:00" "2015-01-05 15:34:00" "2015-01-05 15:34:00" ...
$ m34p1 : POSIXct, format: "2015-01-05 15:35:00" "2015-01-05 15:35:00" "2015-01-05 15:35:00" ...
$ m35p1 : POSIXct, format: "2015-01-05 15:36:00" "2015-01-05 15:36:00" "2015-01-05 15:36:00" ...
$ m36p1 : POSIXct, format: "2015-01-05 15:37:00" "2015-01-05 15:37:00" "2015-01-05 15:37:00" ...
[list output truncated]
How can I display the full list of 602 variables?
回答1:
You can use the argument list.len:
str(df, list.len=ncol(df))
and if you want to print more observations you could set the argument vec.len, also have a look at ?str for documentation of all arguments.
回答2:
By using argument list.len one can choose the number of variables in the data frame to list. There are two options:
a) You choose the number of variables that you want to list;
str(df, list.len = 602) # in this case I'm listing 602 variables.
b) You choose to list the total number of variables of the data frame (as mentioned by user1981275);
str(df, list.len = ncol(df))
Check R help for more info
> ?str
来源：https://stackoverflow.com/questions/28895044/list-output-truncated-how-to-expand-listed-variables-with-str-in-r