问题
I am used to coding in PHP but I am not really proficient with Java and this has been a problem for some time now. I expect it to be a fairly easy solution, however I cannot find any good example code any way I search it, so here goes:
I am programming a game that takes place in a 2d random generated infinite world on a tile based map (nitpicking: I know it will not be truly infinite. I just expect the world to be quite large). The usual approach of map[x][y] multidimensional array started out as a basic idea, but since Java does not provide a way for non-integer (i.e. negative) array key shenanigans like PHP does, I cannot properly have a (-x,+x,-y,+y) coordinate system with array keys.
I need to be able to find the objects on a tile at a specific x,y coordinate as well as finding "adjacent tiles" of a certain tile. (Trivial if I can getObjectAt(x,y), I can get(x+1,y) and so on)
I have read about quad trees and R-trees and the like. The concept is exciting, however I haven't seen any good, simple example implementation in Java. And besides I am not really sure if that is what I need exactly.
Any advice is welcome
Thank you
回答1:
I came to this thread with the same problem, but my solution was to use Map/HashMaps, but these are one dimensional.
To overcome this, instead of using a map within a map (which would be messy and very inefficient) I used a generic Pair class (not something that you'll find in the stock java library) although you could replace this with a Position class (virtually the same code, but not generic, instead integers or floats).
So when defining the map: Map<Pair, Tile> tiles = new HashMap<Pair, Tile>;
For placing tile objects onto the map I used tiles.put(new Pair(x, y), new GrassTile()); and for retrieving the object tiles.get(new Pair(x, y));.
[x/y would be any coordinate you wish to place (this allows negative coordinates without any mess!), "new GrassTile()" is just an example of placing a tile of a certain type during map creation. Obviously - as previously stated - the Pair class is replacable.]
Why not ArrayLists you may ask? Because array lists are much more linear than mapping, and in my opinion are more difficult to add and retrieve tiles, especially on 2 Dimensions.
Update:
For anyone wondering why there isn't a Pair() class in Java, here's an explanation.
回答2:
1) Instead of an array you could use a Map<Integer, Map<Integer, Tile>> or Map<Point, Tile>, which would of course allow negative indexes
2) If you know the dimensions of your world from the start you could just modify your getter to allow the API to accept negatives and [linearly] transform them into positives. So for example if your world is 100x1000 tiles and you want (-5,-100), you would have WorldMap.getTile(-5,-100) which would translate to return tileArray[x+mapWidth/2][y+mapHeight/2]; which is (45,400)
回答3:
Trees, Quad Trees, Binary trees, red and black trees - and all other kinds of trees are USELESS for you (unless you are planning to have a map with a huge forest).
Specialized data structures have their specific uses. Unless you can come up with a good reason why your game needs a spatial index, don't build one. If your typical scenario is "iterate over the visible area, find out what tile is visible at each of the squares", then you need a structure that gives you a quick, random, access to a value stored under a specific key. Such structure is a HashMap (what PHP uses is a kind of a LinkedHashMap, but you were probably not using the "linked" part).
You need to follow xephox's advice (and give him the credit), and that is:
- make a class that describes a location (Pair, Location, Point, whatever);
- make all the fields (probably x and y) final. It is important that a location itself cannot change (it will make your life MUCH easier);
- generate equals and hashcode methods (every IDE will help you with that. Remember that the implementations MUST use both x and y - a wizard in your IDE will help you);
- your map will be: Map map = new HashMap();
The best thing: if you keep using the Map interface, you will not be locked out, and you will be able to make a lot of improvements. Like wrapping the HashMap into an object that creates parts of the map using some algorithmic techniques.
回答4:
I'm not an expert in game programming, but if arrays are OK, you could simply translate your coordinates from (-x, +x) to (0, 2x) (idem for the y axis).
Or if you're used to associative arrays like PHP has, the use the corresponding structure in Java, which is a Map (HashMap would be OK) : define a Coordinate class with appropriate equals and hashCode methods, and use a HashMap<Coordinate>. Making Coordinate immutable makes the code more robust, and allows caching the hashCode.
回答5:
you could try a QuadTree (nice example here: http://www.mikechambers.com/blog/2011/03/21/javascript-quadtree-implementation/ )
回答6:
How about dividing your map into chunks (yes, Minecraft fans, I know where this is used as well :P)? So you have two coordinate systems, both with the same origin:
x/ycoordinatesc1/c2chunk coordinates
A chunk is always a fixed size of real world coordinate (say 128x128). Then you have a class Chunk where you have a fixed array (128x128) with all the information for every pixel. And you store your chunks into a Map<ChunkCoordinates, Chunk> as was already explained by others. I would recommend a HashMap.
Whenever your player is in a certain region, the neccessary chunks are loaded from the map and then you can access the fixed size array in there. If the chunk knows, where it is placed in x/y coordinates, you can even have some support function like Pixel Chunk#getPixel(long x, long y) or so...
Btw: This also gives you an easy way to postpone generation of the whole world until it is really needed: At start, nothing is generated and as soon as a Chunk is accessed in the map, that is not yet generated, you can just generate it then. Or you could fill it up at startup if that's easier for you. (filling an infinite world will take a long time though, even if it is pseudo infinite)
回答7:
I wrote a couple of experimental spare data structures in Java that you might be interested in.
The most interesting one was the Octreap which is what I believe is a completely novel cross between a Treap and an Octree, which had the following features:
- 60 bit world co-ordinates (aprox 1,000,000 * 1,000,000 * 1,000,000 grid)
- Negative co-ordinates supported
- Empty space requires no storage (supports highly sparse worlds)
- Compresses volumes of identical cells (e.g. large blocks of the same material would get stored efficiently)
- O(log n) for reads and writes
回答8:
You probably want to use an implementation of Map. HashMap, SortedMap, etc depending on how much data you intend to store and your access patterns (Sorted Map is very good for sequential access, HashMap is better for random access).
You can either use two-dimensional Maps or munge your 2-d indeces into a key for a 1-d Map.
回答9:
This is two separate questions: how to simulate negative array indicies so you can have an "infinite" map, and how to store tiles efficiently.
On the first question, one hack would be to maintain four separate matricies (matrixes?), one for each quadrant. Then all the indexes can be positive.
On the second question, you need a sparse map. One not-very-efficient way is to have a hashmap of hashmaps. In fact, that could solve the first problem as well:
HashMap<String, HashMap> x = new HashMap()
HashMap<String, Tile> y = new HashMap()
// get the tile at coordinates 1,2
Tile myTile = x.get("1").get("2");
// this would work as well
myTile = x.get("-1").get("-2");
You could do your own Map implementation that took integers as keys and was much, much more efficient.
回答10:
If you want to be really fast and really scalable definitely go with a Sparse Octree.
http://en.wikipedia.org/wiki/Octree
I am not aware of any implementations in Java, but it is trivial. Just store in a single byte a bitfield for which nodes are currently linked and use a linked list to keep those references (for each Octree-node a separate list of max. 8 entries).
回答11:
The hashmap style solutions are terrible for adjacency calculations, they require an iteration of the entire dataset.
Something like a quadtree or octree is perfect EXCEPT that it's not infinite, it's an arbitrary size (world of difference there).
However if you think about it, an ArrayList isn't infinite, it's just an arbitrary size that grows, right?
So a quadtree is sparce and pretty good ad adjacency calculations, except for the "infinite" provision it's perfect. Why not just use one of those sized to 100x what you think you might need (it's sparse, not really a big deal). If you ever get to the point where you are near the edge, allocate a new quadtree that is much bigger.
I believe if you are careful (you may have to implement your own quadtree) you can "upgrade" the quadtree with very little effort and no copying--it should be simply a matter of prefixing all your existing addresses with some bits (the addresses are in binary, quadtrees each bit represents dividing the existing universe in half in one dimension or the other).
来源：https://stackoverflow.com/questions/5226043/java-what-is-a-good-data-structure-for-storing-a-coordinate-map-for-an-infinite