In Go, does a break statement break from a switch/select?

问题

I know that switch/select statements break automatically after every case. I am wondering, in the following code:

for {
    switch sometest() {
    case 0:
        dosomething()
    case 1:
        break
    default:
        dosomethingelse()
    }
}

Does the break statement exit the for loop or just the switch block?

回答1:

Break statements, The Go Programming Language Specification.

A "break" statement terminates execution of the innermost "for", "switch" or "select" statement.
BreakStmt = "break" [ Label ] .
If there is a label, it must be that of an enclosing "for", "switch" or "select" statement, and that is the one whose execution terminates (§For statements, §Switch statements, §Select statements).
L:
  for i < n {
      switch i {
      case 5:
          break L
      }
  }

Therefore, the break statement in your example terminates the switch statement, the "innermost" statement.

回答2:

A hopefully illustrative example:

loop:
for {
        switch expr {
        case foo:
                if condA {
                        doA()
                        break // like 'goto A'
                }

                if condB {
                        doB()
                        break loop // like 'goto B'                        
                }

                doC()
        case bar:
                // ...
        }
A:
        doX()
        // ...
}

B:
doY()
// ....

回答3:

Yes, break breaks the inner switch.

https://play.golang.org/p/SZdDuVjic4

package main

import "fmt"

func main() {

    myloop:for x := 0; x < 7; x++ {
        fmt.Printf("%d", x)
        switch {
        case x == 1:
            fmt.Println("start")
        case x == 5:
            fmt.Println("stop")
            break myloop
        case x > 2:
            fmt.Println("crunching..")
            break
        default:
            fmt.Println("idling..")
        }
    }
}

0idling..
1start
2idling..
3crunching..
4crunching..
5stop

Program exited.

回答4:

Just from a switch block. There's plenty of examples in Golang own code you can examine (compare inner break with outer break).

回答5:

this should explain it.

for{
    x := 1
    switch {
    case x >0:
        fmt.Println("sjus")
    case x == 1:
        fmt.Println("GFVjk")
    default:
        fmt.Println("daslkjh")
    }
}
}

Runs forever

for{
    x := 1
    switch {
    case x >0:
        fmt.Println("sjus")
        break
    case x == 1:
        fmt.Println("GFVjk")
    default:
        fmt.Println("daslkjh")
    }
}
}

Again, runs forever

BUT

package main

import "fmt"

func main() {
d:
for{
x := 1
    switch {
    case x >0:
        fmt.Println("sjus")
        break d
    case x == 1:
        fmt.Println("GFVjk")
    default:
        fmt.Println("daslkjh")
    }
}
}

will print sjus ... clear ?

http://play.golang.org/p/GOvnfI67ih

回答6:

It only exits the switch block.

回答7:

Another use of break for switch is in combination with fallthrough statement. It might need some creativity to use it properly in correct situation, but it is possibly a usable combination.

Here is simple example:

a := 25
fallThrough := true

switch {
case a > 10 :
    fmt.Println("a>10")
    if fallThrough != true {
        break
    }
    fallthrough
case a > 20:
    fmt.Println("a>20")
}

来源：https://stackoverflow.com/questions/11104085/in-go-does-a-break-statement-break-from-a-switch-select

标签

select

switch-statement

break