What is the difference between __init__ and __call__?

问题

I want to know the difference between __init__ and __call__ methods.

For example:

class test:

  def __init__(self):
    self.a = 10

  def __call__(self): 
    b = 20

回答1:

The first is used to initialise newly created object, and receives arguments used to do that:

class Foo:
    def __init__(self, a, b, c):
        # ...

x = Foo(1, 2, 3) # __init__

The second implements function call operator.

class Foo:
    def __call__(self, a, b, c):
        # ...

x = Foo()
x(1, 2, 3) # __call__

回答2:

Defining a custom __call__() method in the meta-class allows the class's instance to be called as a function, not always modifying the instance itself.

In [1]: class A:
   ...:     def __init__(self):
   ...:         print "init"
   ...:         
   ...:     def __call__(self):
   ...:         print "call"
   ...:         
   ...:         

In [2]: a = A()
init

In [3]: a()
call

回答3:

In Python, functions are first-class objects, this means: function references can be passed in inputs to other functions and/or methods, and executed from inside them.

Instances of Classes (aka Objects), can be treated as if they were functions: pass them to other methods/functions and call them. In order to achieve this, the __call__ class function has to be specialized.

def __call__(self, [args ...]) It takes as an input a variable number of arguments. Assuming x being an instance of the Class X, x.__call__(1, 2) is analogous to calling x(1,2) or the instance itself as a function.

In Python, __init__() is properly defined as Class Constructor (as well as __del__() is the Class Destructor). Therefore, there is a net distinction between __init__() and __call__(): the first builds an instance of Class up, the second makes such instance callable as a function would be without impacting the lifecycle of the object itself (i.e. __call__ does not impact the construction/destruction lifecycle) but it can modify its internal state (as shown below).

Example.

class Stuff(object):

    def __init__(self, x, y, range):
        super(Stuff, self).__init__()
        self.x = x
        self.y = y
        self.range = range

    def __call__(self, x, y):
        self.x = x
        self.y = y
        print '__call__ with (%d,%d)' % (self.x, self.y)

    def __del__(self):
        del self.x
        del self.y
        del self.range

>>> s = Stuff(1, 2, 3)
>>> s.x
1
>>> s(7, 8)
__call__ with (7,8)
>>> s.x
7

回答4:

__call__ makes the instance of a class callable. Why would it be required?

Technically __init__ is called once by __new__ when object is created, so that it can be initialized.

But there are many scenarios where you might want to redefine your object, say you are done with your object, and may find a need for a new object. With __call__ you can redefine the same object as if it were new.

This is just one case, there can be many more.

回答5:

__init__ would be treated as Constructor where as __call__ methods can be called with objects any number of times. Both __init__ and __call__ functions do take default arguments.

回答6:

>>> class A:
...     def __init__(self):
...         print "From init ... "
... 
>>> a = A()
From init ... 
>>> a()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method
>>> 
>>> class B:
...     def __init__(self):
...         print "From init ... "
...     def __call__(self):
...         print "From call ... "
... 
>>> b = B()
From init ... 
>>> b()
From call ... 
>>> 

回答7:

I will try to explain this using an example, suppose you wanted to print a fixed number of terms from fibonacci series. Remember that the first 2 terms of fibonacci series are 1s. Eg: 1, 1, 2, 3, 5, 8, 13....

You want the list containing the fibonacci numbers to be initialized only once and after that it should update. Now we can use the __call__ functionality. Read @mudit verma's answer. It's like you want the object to be callable as a function but not re-initialized ever ytime you call it.

Eg:

class Recorder:
    def __init__(self):
        self._weights = []
        for i in range(0, 2):
            self._weights.append(1)
        print self._weights[-1]
        print self._weights[-2]
        print "no. above is from __init__"

    def __call__(self, t):
        self._weights = [self._weights[-1], self._weights[-1] + self._weights[-2]]
        print self._weights[-1]
        print "no. above is from __call__"

weight_recorder = Recorder()
for i in range(0, 10):
    weight_recorder(i)

The output is:

1
1
no. above is from __init__
2
no. above is from __call__
3
no. above is from __call__
5
no. above is from __call__
8
no. above is from __call__
13
no. above is from __call__
21
no. above is from __call__
34
no. above is from __call__
55
no. above is from __call__
89
no. above is from __call__
144
no. above is from __call__

If you observe the output __init__ was called only once that's when the class was instantiated for the first time, later on the object was being called without re-initializing.

回答8:

You can also use __call__ method in favor of implementing decorators.

This example taken from Python 3 Patterns, Recipes and Idioms

class decorator_without_arguments(object):
    def __init__(self, f):
        """
        If there are no decorator arguments, the function
        to be decorated is passed to the constructor.
        """
        print("Inside __init__()")
        self.f = f

    def __call__(self, *args):
        """
        The __call__ method is not called until the
        decorated function is called.
        """
        print("Inside __call__()")
        self.f(*args)
        print("After self.f( * args)")


@decorator_without_arguments
def sayHello(a1, a2, a3, a4):
    print('sayHello arguments:', a1, a2, a3, a4)


print("After decoration")
print("Preparing to call sayHello()")
sayHello("say", "hello", "argument", "list")
print("After first sayHello() call")
sayHello("a", "different", "set of", "arguments")
print("After second sayHello() call")

Output:

回答9:

__init__ is a special method in Python classes, it is the constructor method for a class. It is called whenever an object of the class is constructed or we can say it initialises a new object. Example:

    In [4]: class A:
   ...:     def __init__(self, a):
   ...:         print(a)
   ...:
   ...: a = A(10) # An argument is necessary
10

If we use A(), it will give an error TypeError: __init__() missing 1 required positional argument: 'a' as it requires 1 argument a because of __init__ .

........

__call__ when implemented in the Class helps us invoke the Class instance as a function call.

Example:

In [6]: class B:
   ...:     def __call__(self,b):
   ...:         print(b)
   ...:
   ...: b = B() # Note we didn't pass any arguments here
   ...: b(20)   # Argument passed when the object is called
   ...:
20

Here if we use B(), it runs just fine because it doesn't have an __init__ function here.

回答10:

We can use call method to use other class methods as static methods.

class _Callable:
    def __init__(self, anycallable):
        self.__call__ = anycallable

class Model:

    def get_instance(conn, table_name):

        """ do something"""

    get_instance = _Callable(get_instance)

provs_fac = Model.get_instance(connection, "users")  

回答11:

__call__ allows to return arbitrary values, while __init__ being an constructor returns the instance of class implicitly. As other answers properly pointed out, __init__ is called just once, while it's possible to call __call__ multiple times, in case the initialized instance is assigned to intermediate variable.

>>> class Test:
...     def __init__(self):
...         return 'Hello'
... 
>>> Test()
Traceback (most recent call last):
  File "<console>", line 1, in <module>
TypeError: __init__() should return None, not 'str'
>>> class Test2:
...     def __call__(self):
...         return 'Hello'
... 
>>> Test2()()
'Hello'
>>> 
>>> Test2()()
'Hello'
>>> 

回答12:

Short and sweet answers are already provided above. I wanna provide some practical implementation as compared with Java.

 class test(object):
        def __init__(self, a, b, c):
            self.a = a
            self.b = b
            self.c = c
        def __call__(self, a, b, c):
            self.a = a
            self.b = b
            self.c = c


    instance1 = test(1, 2, 3)
    print(instance1.a) #prints 1

    #scenario 1
    #creating new instance instance1
    #instance1 = test(13, 3, 4)
    #print(instance1.a) #prints 13


    #scenario 2
    #modifying the already created instance **instance1**
    instance1(13,3,4)
    print(instance1.a)#prints 13

Note: scenario 1 and scenario 2 seems same in terms of result output. But in scenario1, we again create another new instance instance1. In scenario2, we simply modify already created instance1. __call__ is beneficial here as the system doesn't need to create new instance.

Equivalent in Java

public class Test {

    public static void main(String[] args) {
        Test.TestInnerClass testInnerClass = new Test(). new TestInnerClass(1, 2, 3);
        System.out.println(testInnerClass.a);

        //creating new instance **testInnerClass**
        testInnerClass = new Test().new TestInnerClass(13, 3, 4);
        System.out.println(testInnerClass.a);

        //modifying already created instance **testInnerClass**
        testInnerClass.a = 5;
        testInnerClass.b = 14;
        testInnerClass.c = 23;

        //in python, above three lines is done by testInnerClass(5, 14, 23). For this, we must define __call__ method

    }

    class TestInnerClass /* non-static inner class */{

        private int a, b,c;

        TestInnerClass(int a, int b, int c) {
            this.a = a;
            this.b = b;
            this.c = c;
        }
    }
}

来源：https://stackoverflow.com/questions/9663562/what-is-the-difference-between-init-and-call