I have a column with pipe separated values such as:
'23|12.1| 450|30|9|78|82.5|92.1|120|185|52|11'
I want to parse this column to fill a table with 12 corresponding columns: month1, month2, month3...month12.
So month1 will have the value 23, month2 the value 12.1 etc...
Is there a way to parse it by a loop or delimeter instead of having to separate one value at a time using substr?
Thanks.
You can use regexp_substr
(10g+):
SQL> SELECT regexp_substr('23|12.1| 450|30|9|', '[^|]+', 1, 1) c1,
2 regexp_substr('23|12.1| 450|30|9|', '[^|]+', 1, 2) c2,
3 regexp_substr('23|12.1| 450|30|9|', '[^|]+', 1, 3) c3
4 FROM dual;
C1 C2 C3
-- ---- ----
23 12.1 450
With a loop in PL/SQL:
SQL> SET SERVEROUTPUT ON
SQL> DECLARE
2 p_tsv VARCHAR2(1000) := '23|12.1| 450|30|9|78|82.5|92.1|120|185|52|11';
3 l_item VARCHAR2(100);
4 BEGIN
5 FOR i IN 1 .. length(p_tsv) - length(REPLACE(p_tsv, '|', '')) + 1 LOOP
6 l_item := regexp_substr(p_tsv, '[^|]+', 1, i);
7 dbms_output.put_line(l_item);
8 END LOOP;
9 END;
10 /
23
12.1
450
30
9
78
82.5
92.1
120
185
52
11
PL/SQL procedure successfully completed
Update
You only have 12 columns, I would write the query direcly without a loop, it will be more performant and easier to maintain than dynamic SQL (not to mention infinitely easier to write):
INSERT INTO your_table
(ID, month1, month2, month3...)
SELECT :p_id,
regexp_substr(:p_tsv, '[^|]+', 1, 1) c1,
regexp_substr(:p_tsv, '[^|]+', 1, 2) c2,
regexp_substr(:p_tsv, '[^|]+', 1, 3) c3
...
FROM dual;
I had 99 problems So I used regular expressions Now I have 100 problems hahahahahahaha just concatenate the delim onto beginning & end of string
pure sql solution:
set define on
undefine string
undefine delim
undefine nth
accept string prompt 'Enter the string: '
accept delim prompt 'Enter the delimiter: '
accept nth prompt 'Enter nth: '
select '&&string' as string,
'&&delim' as delimiter,
&&nth||decode(&&nth,1,'st',2,'nd',3,'rd','th') as nth,
substr('&&delim'||'&&string'||'&delim',
instr('&&delim'||'&&string'||'&&delim', '&&delim', 1, &&nth ) + length('&&delim'),
instr('&&delim'||'&&string'||'&&delim', '&&delim', 1, &&nth + 1 ) - instr('&&delim'||'&&string'||'&&delim', '&&delim', 1, &&nth ) - length('&&delim')
) as val from dual
/
来源:https://stackoverflow.com/questions/2942052/parsing-pipe-delimited-string-into-columns