Lazy mapping with hibernate tools?

问题

I have two tables A and B in my database. I the table B I have a reference to the table A by an Integer idA. (idA is a foreign key for B) When I do reverse engineering using hibernate-tools, I generate two Java objects.

public class A{
  int id;
} 

and

public class B{
  int id;
  A a;
} 

But I want to have

public class B{
  int id;
  int idA;
}  

How can I do this?

Thanks,

回答1:

So I found a solution: create a custom ReverseEngineeringStrategy and change the return of excludeForeignKeyAsManytoOne method to true.

public class MyReverseEngineeringStrategy extends DelegatingReverseEngineeringStrategy {

    public MyReverseEngineeringStrategy(ReverseEngineeringStrategy delegate) {
        super(delegate);
    }

    @Override
    public boolean excludeForeignKeyAsManytoOne(String keyname, TableIdentifier fromTable, List fromColumns, TableIdentifier referencedTable, List referencedColumns) {
        return true;
                }

}

回答2:

I think for this you have to update your class manually and then remove any @OneToOne annotations or similar tags in XML mapping.

By default, Hibernate suggests you to have entity mapped so you can use at once, without having to fetch it explicitly.

来源：https://stackoverflow.com/questions/23739937/lazy-mapping-with-hibernate-tools