Three-way compare function for Arrays in Javascript

问题

There have been other questions about How to compare arrays in JavaScript?. What I want to know is the most straightforward way to write/use a three-way comparison function like the one required by Array.sort(). Here's an example using the default one which doesn't work well:

> [ [4,5,10], [4,5,6], [4,1,2] ].sort() // no compare function, uses the default one
[ [ 4, 1, 2 ],
  [ 4, 5, 10 ], // oops, string sorting makes 10 < 6
  [ 4, 5, 6 ] ]

This is what I came up with:

// return -1 if lhs is "less" than rhs, +1 if "greater", and 0 if equal
// if lhs and rhs have different lengths, only the shorter part will be considered
function compareArrays(lhs, rhs) {
  for (var ii = 0; ii < lhs.length; ii++) {
    if (lhs[ii] < rhs[ii]) {
      return -1;
    } else if (lhs[ii] > rhs[ii]) {
      return 1;
    }
  }
  return 0;
}

Which gives us what we want:

> [ [4,5,10], [4,5,6], [4,1,2] ].sort(compareArrays)
[ [ 4, 1, 2 ],
  [ 4, 5, 6 ],
  [ 4, 5, 10 ] ]

Is there something more like a one-liner, or must I define my own function whenever I want to do this?

Supporting old browsers is not a requirement. Using libraries like jQuery or Underscore is OK.

One way to look at this is "The first nonzero value from a standard three-way compare applied to each pair of elements." But even then I haven't found a good fit in existing libraries.

回答1:

I'd go with a generic comparison-maker function to be used in a functional way:

function compareArrays(compareItems) {
    return function(a, b) {
        for (var r, i=0, l=Math.min(a.length, b.length); i<l; i++)
            if (0 != (r = compareItems(a[i], b[i])))
                return r;
        return a.length - b.length;
     };
}
// Examples:
var compareNumberArrays = compareArray(function(a,b){ return a-b; }),
    compareGenericArrays = compareArray(function(a,b){ return +(a>b)||-(b>a); });

Now you can use

[ [4,5,10], [4,5,6], [4,1,2], [4,5] ].sort(compareNumberArrays)

Is there something more like a one-liner, or must I define my own function whenever I want to do this?

Comparing arrays is too complex for a one-liner, you should use a helper function. There's no built-in one that you can use everywhere.

回答2:

Probably not the shortest possible, but the fewest lines I can get to sensibly is:

function compareArrays(lhs, rhs) {
  var result;
  lhs.some(function(v, i) {
    return (result = v - rhs[i]);
  });
  return result;
}

or less sensibly:

function compareArrays(lhs, rhs, r) {
  lhs.some(function(v, i) {return (r = v - rhs[i])});
  return r;
}

Edit

Seems you don't want numbers. The compare part can be any relationship you want, e.g. for strings:

function compareArrays(lhs, rhs, r) {
  lhs.some(function(v, i) {return (r = v < rhs[i]? -1 : v > rhs[i]? 1 : 0)});
  return r;
}

[['a','b','c'],['a','c','d'],['a','b','d']].sort(compareArrays) // a,b,c,a,b,d,a,c,d

But the compare function needs to know what it's getting so it doesn't sort numbers as strings or strings as numbers (and so on…).

回答3:

If you know that they are always triplets of numbers (arrays of length 3), you could do this:

function combineNum(array) {
    return (array[0] * 100) + (array[1] * 10) + array[2];
}

function compareArrays(lhs, rhs) {
    return combineNum(rhs) - combineNum(lhs);
}

来源：https://stackoverflow.com/questions/23881838/three-way-compare-function-for-arrays-in-javascript

标签

javascript

arrays

three-way-merge