bc
doesn't like numbers expressed in scientific notation (aka exponential notation).
$ echo "3.1e1*2" | bc -l
(standard_in) 1: parse error
but I need to use it to handle a few records that are expressed in this notation. Is there a way to get bc
to understand exponential notation? If not, what can I do to translate them into a format that bc
will understand?
Unfortunately, bc doesn't support scientific notation.
However, it can be translated into a format that bc can handle, using extended regex as per POSIX in sed:
sed -E 's/([+-]?[0-9.]+)[eE]\+?(-?)([0-9]+)/(\1*10^\2\3)/g' <<<"$value"
you can replace the "e" (or "e+", if the exponent is positive) with "*10^", which bc will promptly understand. This works even if the exponent is negative or if the number is subsequently multiplied by another power, and allows keeping track of significant digits.
If you need to stick to basic regex (BRE), then this should be used:
sed 's/\([+-]\{0,1\}[0-9]*\.\{0,1\}[0-9]\{1,\}\)[eE]+\{0,1\}\(-\{0,1\}\)\([0-9]\{1,\}\)/(\1*10^\2\3)/g' <<<"$value"
From Comments:
A simple bash pattern match could not work (thanks @mklement0) as there is no way to match a e+ and keep the - from a e- at the same time.
A correctly working perl solution (thanks @mklement0)
$ perl -pe 's/([-\d.]+)e(?:\+|(-))?(\d+)/($1*10^$2$3)/gi' <<<"$value"
Thanks to @jwpat7 and @Paul Tomblin for clarifying aspects of sed's syntax, as well as @isaac and @mklement0 for improving the answer.
Edit:
The answer changed quite a bit over the years. The answer above is the latest iteration as of 17th May 2018. Previous attempts reported here were a solution in pure bash (by @ormaaj) and one in sed (by @me), that fail in at least some cases. I'll keep them here just to make sense of the comments, which contain much nicer explanations of the intricacies of all this than this answer does.
value=${value/[eE]+*/*10^} ------> Can not work.
value=`echo ${value} | sed -e 's/[eE]+*/\\*10\\^/'` ------> Fail in some conditions
Let me try to summarize the existing answers, with comments on each below:
(a) If you indeed need to use
bc
for arbitrary-precision calculations - as the OP does - use the OP's own clever approach, which textually reformats the scientific notation to an equivalent expression thatbc
understands.If potentially losing precision is not a concern,
- (b) consider using
awk
orperl
asbc
alternatives; both natively understand scientific notation, as demonstrated in jwpat7's answer for awk. - (c) consider using
printf '%.<precision>f'
to simply textually convert to regular floating point representation (decimal fractions, without thee
/E
) (a solution proposed in a since-deleted post by ormaaj).
- (b) consider using
(a) Reformatting scientific notation to an equivalent bc
expression
The advantage of this solution is that precision is preserved: the textual representation is transformed into an equivalent textual representation that bc
can understand, and bc
itself is capable of arbitrary-precision calculations.
See the OP's own answer, whose updated form is now capable of transforming an entire expression containing multiple numbers in exponential notation into an equivalent bc
expression.
(b) Using awk
or perl
instead of bc
as the calculator
Note: The following approaches assume use of the built-in support for double-precision floating-point values in awk
and perl
.
As is in inherent in floating-point arithmetic,
"given any fixed number of bits, most calculations with real numbers will produce quantities that cannot be exactly represented using that many bits. Therefore the result of a floating-point calculation must often be rounded in order to fit back into its finite representation. This rounding error is the characteristic feature of floating-point computation." (http://docs.oracle.com/cd/E19957-01/806-3568/ncg_goldberg.html)
That said,
GNU awk offers the option to be built with support for arbitrary-precision arithmetic - see https://www.gnu.org/software/gawk/manual/html_node/Gawk-and-MPFR.html; however, distributions may or may not include that support - verify support by checking the output from
gawk --version
forGNU MPFR
andGNU MP
.
If support is available, you must activate it with-M
(--bignum
) in a given invocation.Perl offers optional arbitrary-precision decimal support via the
Math::BigFloat
package - see https://metacpan.org/pod/Math::BigFloat
awk
awk
natively understands decimal exponential (scientific) notation.
(You should generally only use decimal representation, because awk
implementations differ with respect to whether they support number literals with other bases.)
awk 'BEGIN { print 3.1e1 * 2 }' # -> 62
If you use the default print
function, the OFMT
variable controls the output format by way of a printf
format string; the (POSIX-mandated) default is %.6g
, meaning 6 significant digits, which notably includes the digits in the integer part.
Note that if the number in scientific notation is supplied as input (as opposed to a literal part of the awk program), you must add +0
to force it to the default output format, if used by itself with print
:
Depending on your locale and the awk
implementation you use, you may have to replace the decimal point (.
) with the locale-appropriate radix character, such as ,
in a German locale; applies to BSD awk
, mawk
, and to GNU awk
with the --posix
option.
awk '{ print $1+0 }' <<<'3.1e1' # -> 31; without `+0`, output would be the same as input
Modifying variable OFMT
changes the default output format (for numbers with fractional parts; (effective) integers are always output as such).
Alternatively, use the printf
function with an explicit output format:
awk 'BEGIN { printf "%.4f", 3.1e1 * 2.1234 }' # -> 65.8254
Perl
perl
too natively understands decimal exponential (scientific) notation.
Note: Perl, unlike awk, isn't available on all POSIX-like platforms by default; furthermore, it's not as lightweight as awk.
However, it offers more features than awk, such as natively understanding hexadecimal and octal integers.
perl -le 'print 3.1e1 * 2' # -> 62
I'm unclear on what Perl's default output format is, but it appears to be %.15g
.
As with awk, you can use printf
to choose the desired output format:
perl -e 'printf "%.4f\n", 3.1e1 * 2.1234' # -> 65.8254
(c) Using printf
to convert scientific notation to decimal fractions
If you simply want to convert scientific notation (e.g., 1.2e-2
) into a decimal fraction (e.g., 0.012
), printf '%f'
can do that for you.
Note that you'll convert one textual representation into another via floating-point arithmetic, which is subject to the same rounding errors as the awk
and perl
approaches.
printf '%.4f' '1.2e-2' # -> '0.0120'; `.4` specifies 4 decimal digits.
One can use awk for this; for example,
awk '{ print +$1, +$2, +$3 }' <<< '12345678e-6 0.0314159e2 54321e+13'
produces (via awk's default format %.6g) output like12.3457 3.14159 543210000000000000
while commands like the following two produce the output shown after each, given that file edata
contains data as shown later.
$ awk '{for(i=1;i<=NF;++i)printf"%.13g ",+$i; printf"\n"}' < edata`
31 0.0312 314.15 0
123000 3.1415965 7 0.04343 0 0.1
1234567890000 -56.789 -30
$ awk '{for(i=1;i<=NF;++i)printf"%9.13g ",+$i; printf"\n"}' < edata
31 0.0312 314.15 0
123000 3.1415965 7 0.04343 0 0.1
1234567890000 -56.789 -30
$ cat edata
3.1e1 3.12e-2 3.1415e+2 xyz
123e3 0.031415965e2 7 .4343e-1 0e+0 1e-1
.123456789e13 -56789e-3 -30
Also, regarding solutions using sed
, it probably is better to delete the plus sign in forms like 45e+3
at the same time as the e
, via regex [eE]+*
, rather than in a separate sed
expression. For example, on my linux machine with GNU sed version 4.2.1 and bash version 4.2.24, commandssed 's/[eE]+*/*10^/g' <<< '7.11e-2 + 323e+34'
sed 's/[eE]+*/*10^/g' <<< '7.11e-2 + 323e+34' | bc -l
produce output7.11*10^-2 + 323*10^34
3230000000000000000000000000000000000.07110000000000000000
You can also define a bash function which calls awk (a good name would be the equal sign "="):
= ()
{
local in="$(echo "$@" | sed -e 's/\[/(/g' -e 's/\]/)/g')";
awk 'BEGIN {print '"$in"'}' < /dev/null
}
Then you can use all type of floating point math in the shell. Note that square brackets are used here instead of round brackets, since the latter would have to be protected from the bash by quotes.
> = 1+sin[3.14159] + log[1.5] - atan2[1,2] - 1e5 + 3e-10
0.94182
Or in a script to assign the result
a=$(= 1+sin[4])
echo $a # 0.243198
Luckily there is printf, which does the formatting job:
The above example:
printf "%.12f * 2\n" 3.1e1 | bc -l
Or a float comparison:
n=8.1457413437133669e-02
m=8.1456839223809765e-02
n2=`printf "%.12f" $n`
m2=`printf "%.12f" $m`
if [ $(echo "$n2 > $m2" | bc -l) == 1 ]; then
echo "n is bigger"
else
echo "m is bigger"
fi
Piping version of OPs accepted answer
$ echo 3.82955e-5 | sed 's/[eE]+*/\*10\^/'
3.82955*10^-5
Piping the input to the OPs accepted sed command gave extra backslashes like
$ echo 3.82955e-5 | sed 's/[eE]+*/\\*10\\^/'
3.82955\*10\^-5
try this (found this in an example for a CFD input data for processing with m4:)
T0=4e-5
deltaT=2e-6
m4 <<< "esyscmd(perl -e 'printf (${T0} + ${deltaT})')"
Try this: (using bash)
printf "scale=20\n0.17879D-13\n" | sed -e 's/D/*10^/' | bc
or this:
num="0.17879D-13"; convert="`printf \"scale=20\n$num\n\" | sed -e 's/D/*10^/' | bc`" ; echo $convert
.00000000000001787900
num="1230.17879"; convert="`printf \"scale=20\n$num\n\" | sed -e 's/D/*10^/' | bc`" ; echo $convert
1230.17879
If you have positive exponents you should use this:
num="0.17879D+13"; convert="`printf \"scale=20\n$num\n\" | sed -e 's/D+/*10^/' -e 's/D/*10^/' | bc`" ; echo $convert
1787900000000.00000
That last one would handle every numbers thrown at it. You can adapt the 'sed' if you have numbers with 'e' or 'E' as exponents.
You get to chose the scale you want.
I managed to do it with a little hack. You can do something like this -
scientific='4.8844221e+002'
base=$(echo $scientific | cut -d 'e' -f1)
exp=$(($(echo $scientific | cut -d 'e' -f2)*1))
converted=$(bc -l <<< "$base*(10^$exp)")
echo $converted
>> 488.4422100
来源:https://stackoverflow.com/questions/12882611/how-to-get-bc-to-handle-numbers-in-scientific-aka-exponential-notation