How to break out of while loop in Python?

非 Y 不嫁゛ 提交于 2019-11-28 06:51:44
John La Rooy

A couple of changes mean that only an R or r will roll. Any other character will quit

import random

while True:
    print('Your score so far is {}.'.format(myScore))
    print("Would you like to roll or quit?")
    ans = input("Roll...")
    if ans.lower() == 'r':
        R = np.random.randint(1, 8)
        print("You rolled a {}.".format(R))
        myScore = R + myScore
    else:
        print("Now I'll see if I can break your score...")
        break

What I would do is run the loop until the ans is Q

ans=(R)
while not ans=='Q':
    print('Your score is so far '+str(myScore)+'.')
    print("Would you like to roll or quit?")
    ans=input("Roll...")
    if ans=='R':
        R=random.randint(1, 8)
        print("You rolled a "+str(R)+".")
        myScore=R+myScore
ans=(R)
while True:
    print('Your score is so far '+str(myScore)+'.')
    print("Would you like to roll or quit?")
    ans=input("Roll...")
    if ans=='R':
        R=random.randint(1, 8)
        print("You rolled a "+str(R)+".")
        myScore=R+myScore
    else:
        print("Now I'll see if I can break your score...")
        ans = False
        break

Don't use while True and break statements. It's bad programming.

Imagine you come to debug someone else's code and you see a while True on line 1 and then have to trawl your way through another 200 lines of code with 15 break statements in it, having to read umpteen lines of code for each one to work out what actually causes it to get to the break. You'd want to kill them...a lot.

The condition that causes a while loop to stop iterating should always be clear from the while loop line of code itself without having to look elsewhere.

Phil has the "correct" solution, as it has a clear end condition right there in the while loop statement itself.

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