How can I enumerate through the possible "values" of a discriminated union in F#?
I want to know if is there something like Enum.GetValues(Type)
for discriminated unions, tough I am not sure over what kind of data I would enumerate. I would like to generate a list or array of a discriminated union with one item for each option.
Yes, F# has it's own reflection layer build on top of .NET's reflection to help you make sense of types that are specific to F#, like discriminating unions. Here's the code that will let you enumerate a union's cases:
open Microsoft.FSharp.Reflection
type MyDU =
| One
| Two
| Three
let cases = FSharpType.GetUnionCases typeof<MyDU>
for case in cases do printfn "%s" case.Name
To slightly extend Robert's example - even if you don't have an instance of the discriminated union, you can use F# reflection to get the information about the type (such as types of the arguments of individual cases). The following extends Robert's sample ans it also prints the types of arguments:
open Microsoft.FSharp.Reflection
let ty = typeof<option<int>>
let cases = FSharpType.GetUnionCases ty
printfn "type %s =" ty.FullName
for case in cases do
printf "| %s" case.Name
let fields = case.GetFields()
if fields.Length > 0 then
printf " of"
for fld in fields do
printf " %s " fld.PropertyType.FullName
printfn ""
For example, for option<int>
type, you'll get (I slightly simplified the output):
type Microsoft.FSharp.Core.FSharpOption`1[System.Int32] =
| None
| Some of System.Int32
There are many interesting uses for this information - for example, you could generate DB schema from F# unions or to create functions that will parse XML into a discriminated union (that describes the structure). I talked about the XML processing sample at GOTO conference earlier this year.
If your discriminated union is only made of plain identifiers (no case storing any data, this might be what you need: gist
open Microsoft.FSharp.Reflection
module SimpleUnionCaseInfoReflection =
// will crash if 'T contains members which aren't only tags
let Construct<'T> (caseInfo: UnionCaseInfo) = FSharpValue.MakeUnion(caseInfo, [||]) :?> 'T
let GetUnionCaseInfoAndInstance<'T> (caseInfo: UnionCaseInfo) = (caseInfo, Construct<'T> caseInfo)
let AllCases<'T> =
FSharpType.GetUnionCases(typeof<'T>)
|> Seq.map GetUnionCaseInfoAndInstance<'T>
#load "SimpleUnionCaseInfoReflection.fs"
type Foos = Foo | Bar | Baz
SimpleUnionCaseInfoReflection.AllCases<Foos> |> Seq.iter (fun (caseInfo, instance) ->printfn "name: %s instance: %O is Bar? : %b" caseInfo.Name instance (instance.Equals(Foos.Bar)))
(*
> name: Foo instance: FSI_0055+Foos is Bar? : false
> name: Bar instance: FSI_0055+Foos is Bar? : true
> name: Baz instance: FSI_0055+Foos is Bar? : false
*)
It's hard to see how this could possibly work without also having an instance since discrimination unions can carry values.
If you had a type like this for example:
type Status = Success of string | Error of System.Exception | Timeout
What would you except your array to contain for Success or Error in this case?
来源:https://stackoverflow.com/questions/6997083/how-to-enumerate-a-discriminated-union-in-f