问题
I'm kinda new to PHP.
I've got two different hosts and I want my php page in one of them to show me a directory listing of the other. I know how to work with opendir() on the same host but is it possible to use it to get access to another machine?
Thanks in advance
回答1:
You could use PHP's FTP Capabilities to remotely connect to the server and get a directory listing:
// set up basic connection
$conn_id = ftp_connect('otherserver.example.com');
// login with username and password
$login_result = ftp_login($conn_id, 'username', 'password');
// check connection
if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has failed!";
exit;
}
// upload the file
$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY);
// check upload status
if (!$upload) {
echo "FTP upload has failed!";
} else {
echo "Uploaded $source_file to $ftp_server as $destination_file";
}
// Retrieve directory listing
$files = ftp_nlist($conn_id, '/remote_dir');
// close the FTP stream
ftp_close($conn_id);
回答2:
Try:
<?php
$dir = opendir('ftp://user:pass@domain.tld/path/to/dir/');
while (($file = readdir($dir)) !== false) {
if ($file[0] != ".") $str .= "\t<li>$file</li>\n";
}
closedir($dir);
echo "<ul>\n$str</ul>";
回答3:
I was unable to get the FTP suggestions to work so I took a more unconventional route, basically it yanks the html from the "Index of" page and extracts the filenames.
Index page:
Index of /files
Extraction code:
$dir = "http://www.yoursite.com/files/";
$contents = file_get_contents($dir);
$lines = explode("\n", $contents);
foreach($lines as $line) {
if($line[1] == "l") { // matches the <li> tag and skips 'Parent Directory'
$line = preg_replace('/<[^<]+?>/', '', $line); // removes tags, curtousy of http://stackoverflow.com/users/154877/marcel
echo trim($line) . "\n";
}
}
来源:https://stackoverflow.com/questions/5292984/php-opendir-on-another-server