问题
Are any of you aware of a library that helps you build/manipulate SQL queries, that supports JOIN's?
It would give a lot of flexibility i'd think if you have something where you could return an object, that has some query set, and still be able to apply JOIN's to it, subqueries and such.
I've search around, and have only found SQL Builder, which seems very basic, and doesn't support joins. Which would be a major feature that would really make it useful.
回答1:
Maybe you can try an ORM, like Propel or Doctrine, they have a nice programmatic query language, and they return you arrays of objects that represent rows in your database...
For example with Doctrine you can do joins like this:
$q = Doctrine_Query::create();
$q->from('User u')
->leftJoin('u.Group g')
->innerJoin('u.Phonenumber p WITH u.id > 3')
->leftJoin('u.Email e');
$users = $q->execute();
And with Propel:
$c = new Criteria(AuthorPeer::DATABASE_NAME);
$c->addJoin(AuthorPeer::ID, BookPeer::AUTHOR_ID, Criteria::INNER_JOIN);
$c->addJoin(BookPeer::PUBLISHER_ID, PublisherPeer::ID, Criteria::INNER_JOIN);
$c->add(PublisherPeer::NAME, 'Some Name');
$authors = AuthorPeer::doSelect($c);
and you can do a lot more with both...
回答2:
Zend_Db_Select from the Zend_Db package of the Zend Framework can do such things as:
// Build this query:
// SELECT p."product_id", p."product_name", l.*
// FROM "products" AS p JOIN "line_items" AS l
// ON p.product_id = l.product_id
$select = $db->select()
->from(array('p' => 'products'), array('product_id', 'product_name'))
->join(array('l' => 'line_items'), 'p.product_id = l.product_id');
(from Example 11.54. Example of the join() method in the Zend Framework Manual)
If you don't like to run a full-blown ORM package, this could be the way to go.
回答3:
I highly recommend CakePHP. It creates joins for you automatically, based on the associations between tables.
Say if you were writing a blog:
app/model/post.php:
class Post extends AppModel {
var $hasMany = array('Comment');
}
app/controller/posts_controller.php:
function view($id) {
$this->set('post', $this->Post->read(null, $id));
}
app/views/posts/view.ctp:
<h2><?php echo $post['Post']['title']?></h2>
<p><?php echo $post['Post']['body']; /* Might want Textile/Markdown here */ ?></p>
<h3>Comments</h3>
<?php foreach($post['Comment'] as $comment) { ?>
<p><?php echo $comment['body']?></p>
<p class="poster"><?php echo $comment['name']?></p>
<?php } ?>
That would be all you have to write to view a blog post, your database schema is read and cached. As long as you keep it consistent with the conventions, you don't have to tell cake anything about how your table is set up.
posts:
id INT
body TEXT
created DATETIME
comments:
id INT
body TEXT
name VARCHAR
post_id INT
It has adapters to support MySQL, MSSQL, PostgreSQL, SQLite, Oracle and others. You can also wrap webservices as models, and even get it to do joins between data in your database and remote data! It's very clever stuff.
Hope this helps :)
回答4:
superfast SQLObject based IteratorQuery from pastaPHP
iterates over resource
foreach(_from('users u')
->columns("up.email_address AS EmailAddress", "u.user_name AS u.UserName")
->left('userprofiles up', _eq('u.id', _var('up.id')))
->where(_and()->add(_eq('u.is_active',1)))
->limit(0,10)
->order("UserName")
->execute("myConnection") as $user){
echo sprintf(
'<a href="mailto:%s">%s</a><br/>',
$user->EmailAdress,
$user->UserName
);
}
回答5:
FluentPDO looks nice if you're already using PDO: https://github.com/envms/fluentpdo
回答6:
I would advise using a PHP framework such as Symfony which uses Propel by default and can use Doctrine if you wish.
CakePHP also uses an ORM, but I don't know which one.
回答7:
This seems to be a SQL builder with complex join support: http://laravel.com/docs/queries
回答8:
I use the query builder from the phptoolcase library, it uses pdo connector, has join support.
http://phptoolcase.com/guides/ptc-qb-guide.html
You can use it with the connection manager fro the library to setup multiple database connection very quickly.
回答9:
Try magsql https://github.com/maghead/magsql, a SQL builder designed for performance written in PHP, comes with join support and cross-platform SQL generation.
It's currently used in the fastest pure PHP orm "maghead"
回答10:
You can use lenkorm it's very easy:
select('contents)->left('categories ON categories.category.id = contents.category_id)->where('content_id = 1')->result();
or you can use as:
select('contents)->left('categories->using(categoru_id)->where('content_id = 1')->result();
Download it from github
来源:https://stackoverflow.com/questions/216138/sql-builder-for-php-with-join-support