PrintWindow and BitBlt of hidden windows

孤街浪徒 提交于 2019-11-28 04:45:07

问题


My program is taking screenshots of other application windows to automate some tasks on them. Those windows can be hidden offscreen or obscured by other windows from time to time.

To reduce clutter, I have removed any error checking from the code listings. I am preparing the both types of screenshots with

// Get size of the target window.
RECT clientRect;
GetClientRect(hwnd, &clientRect);
int width = clientRect.right - clientRect.left;
int height = clientRect.bottom - clientRect.top;
// Create a memory device context.
HDC windowDC = GetDC(hwnd);
HDC memoryDC = CreateCompatibleDC(windowDC);
// Create a bitmap for rendering.
BITMAPINFO bitmapInfo;
ZeroMemory(&bitmapInfo, sizeof(BITMAPINFO));
bitmapInfo.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
bitmapInfo.bmiHeader.biWidth = width;
bitmapInfo.bmiHeader.biHeight = -height;
bitmapInfo.bmiHeader.biPlanes = 1;
bitmapInfo.bmiHeader.biBitCount = 32;
bitmapInfo.bmiHeader.biCompression = BI_RGB;
bitmapInfo.bmiHeader.biSizeImage = width * height * 4;
RGBQUAD* buffer;
HBITMAP bitmap = CreateDIBSection(windowDC, &bitmapInfo, DIB_RGB_COLORS, (void**)&buffer, 0, 0);
HGDIOBJ previousObject = SelectOBject(memoryDC, bitmap);

then I am taking the actual screenshots with either

PrintWindow(hwnd, memoryDC, PW_CLIENTONLY); 
GdiFlush();

or

UpdateWindow(hwnd);
BitBlt(memoryDC, 0, 0, width, height, windowDC, 0, 0, SRCCOPY);
GdiFlush();

then I copy the buffer contents to a vector

std::vector<RGBQUAD> pixels;
pixels.resize(width * height, { 0, 0, 0, 0 });
memcpy(&pixels[0], buffer, bitmapInfo.bmiHeader.biSizeImage);

and finally I am cleaning everything up with

ReleaseDC(hwnd, windowDC);
SelectObject(memoryDC, previousObject);
DeleteDC(memoryDC);
DeleteObject(bitmap);

I have a three of questions about the code above:

  1. Do I need to call GdiFlush()? I read the documentation and did some Google research, but I am still not sure if it makes sense to call it or not.
  2. Does the call to UpdateWindow() right before the BitBlt() make a difference? Does this help, so that the Device Context contents are "more up to date"?
  3. Am I right in assuming that for PrintWindow() all the work is done from within the target application (increasing the target application's CPU usage), while BitBlt() is fully executed from within the calling thread (thus increasing the CPU usage of my own application)?
  4. Under which circumstances might any of the above functions fail? I know that BitBlt() only works for hidden windows if Desktop Composition (DWM) is enabled, but on a very small set of systems (Windows 8/10) BitBlt() and PrintWindow() seem to fail for windows for which they work just fine on other systems (even though DWM is enabled). I could not spot any patterns as to why, though.

Any information is appreciated, thanks.


回答1:


finally, after some hours of investigation, I found a solution for that issue: It's sufficient to call the following command within the ACTIVATE event of the form to be imaged (example in VB coding):

Call SetWindowLong(me.hwnd, GWL_EXSTYLE, WS_EX_LAYERED)

Whereas this command is defined as follows:

Private Declare Function SetWindowLong Lib "User32" Alias "SetWindowLongA" (ByVal hwnd As Long, ByVal nIndex As Long, ByVal dwNewLong As Long) As Long

Private Const GWL_EXSTYLE = (-20)

Private Const WS_EX_LAYERED = &H80000

Please try this!

Best regards, Bambi66




回答2:


After more than two months I finally realized that this only occurs with the Windows update 1809 from late 2018. Apparently, Windows changed the way it handles clipping with that update so that the Device Context contents are no longer updated for parts of windows that are located offscreen.

To answer the individual questions:

1) GdiFlush doesn't seem to make a difference, at least from what I can tell so far.

2) Still not 100% sure about it, but I also think it doesn't make a difference.

3) Still no idea.

4) See answer above.



来源:https://stackoverflow.com/questions/53710135/printwindow-and-bitblt-of-hidden-windows

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