Simplest way to increment a date in PHP?

问题

Say I have a string coming in, \"2007-02-28\", what\'s the simplest code I could write to turn that into \"2007-03-01\"? Right now I\'m just using strtotime(), then adding 24*60*60, then using date(), but just wondering if there is a cleaner, simpler, or more clever way of doing it.

回答1:

A clean way is to use strtotime()

$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);

Will give you the 2007-03-01

回答2:

It's cleaner and simpler to add 86400. :)

The high-tech way is to do:

$date = new DateTime($input_date);
$date->modify('+1 day');
echo $date->format('Y-m-d');

but that's really only remotely worthwhile if you're doing, say, a sequence of transformations on the date, rather than just finding tomorrow.

回答3:

You can do the addition right inside strtotime, e.g.

 $today="2007-02-28";
 $nextday=strftime("%Y-%m-%d", strtotime("$today +1 day"));

回答4:

Another way is to use function mktime(). It is very useful function...

$date = "2007-02-28";
list($y,$m,$d)=explode('-',$date);
$date2 = Date("Y-m-d", mktime(0,0,0,$m,$d+1,$y));

but I think strtotime() is better in that situation...

回答5:

The simplest way...

echo date('Y-m-d',strtotime("+1 day"));    //from today

OR from specified date...

echo date('Y-m-d',strtotime("+1 day", strtotime('2007-02-28')));

回答6:

Hello you can try this below especially if you are french

$date = date('l j F Y');
#increment the date
$date2 = date('l j F Y', strtotime("+7 day"));

to translate in french you can use the setlocale() function or the function below :

function fr_date($date){

    $date = explode(' ', $date);

    $date = str_replace('Monday','Lundi',$date);
    $date = str_replace('Tuesday','Mardi',$date);
    $date = str_replace('Wednesday','Mercredi',$date);
    $date = str_replace('Thursday','Jeudi',$date);
    $date = str_replace('Friday','Vendredi',$date);
    $date = str_replace('Saturday','Samedi',$date);
    $date = str_replace('Sunday','Dimanche',$date);

    $date = str_replace('January','Janvier',$date);
    $date = str_replace('February','Février',$date);
    $date = str_replace('March','Mars',$date);
    $date = str_replace('April','Avril',$date);
    $date = str_replace('May','Mai',$date);
    $date = str_replace('June','Juin',$date);
    $date = str_replace('July','Juillet',$date);
    $date = str_replace('August','Août',$date);
    $date = str_replace('September','Septembre',$date);
    $date = str_replace('October','Octobre',$date);
    $date = str_replace('November','Novembre',$date);
    $date = str_replace('December','Décembre',$date);

    $date = implode(' ',$date);
    return $date;

}

回答7:

$your_date = strtotime("1month", strtotime(date("Y-m-d")));
 $new_date = date("Y-m-d", $your_date++);

回答8:

 $early_start_date = date2sql($_POST['early_leave_date']);


        $date = new DateTime($early_start_date);
        $date->modify('+1 day');


        $date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
        $date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);

        $interval = date_diff($date_a, $date_b);

来源：https://stackoverflow.com/questions/660501/simplest-way-to-increment-a-date-in-php

标签

php

datetime

date

strtotime

date-manipulation