问题
I was looking at this article and am struggling to follow the VB.NET example that explains lifted operators. There doesn\'t seem to be an equivalent C# example or tutorial. I don\'t have much experience with operator overloading in general, so trying to come to terms with the VB.NET equivalent whilst reading up on nullable types probably isn\'t the best place to start...
Would anyone be able to provide an explanation of lifted operators and how they are used by nullable types? Does it just mean that the nullable type does not itself overload operators and will use the operators from the underlying type that it represents?
There doesn\'t seem to be much information on SO about lifted operators, so hopefully this can help some others out too.
回答1:
Lifted operators are operators which work over nullable types by "lifting" the operators which already exist on the non-nullable form. So for example, if you do:
int? x = 10;
int? y = 10;
int? z = x + y;
That "+" operator is lifted. It doesn't actually exist on Nullable<int> but the C# compiler acts as if it does, generating code to do the right thing. (For the most case, that's a matter of checking whether either operand is null; if so, the result is null. Otherwise, unwrap both operands to their non-nullable values, use the normal operator, and then wrap the result back into a nullable value. There are a few special cases around comparisons though.)
See section 6.4.2 (lifted conversion operators) and 7.3.7 (lifted operators) of the C# spec for more information.
回答2:
Lifted operators allow predefined and user-defined operators that work for non-nullable types to be used for their nullable forms as well.
int i = 5;
int? j = 6;
int? k = j + i; // 11
int? q = i + null; // null - Shows a warning the result of the expression is always null of type int?
int r = i + null; // Throws an error the result of expression is always null of type int?
来源：https://stackoverflow.com/questions/3370110/what-are-lifted-operators