问题
Use case:
class A {
static int s_common;
public:
static int getCommon () const { s_common; };
};
Typically this results in an error as:
error: static member function ‘static int A::getCommon()’ cannot have cv-qualifier
This is because const
ness applies only to the object pointed by this
, which is not present in a static
member function.
However had it been allowed, the static
member function's "const"ness could have been easily related to the static
data members.
Why is this feature is not present in C++; any logical reason behind it ?
回答1:
cv-qualifiers
affect the function's signature. So you could have:
class A {
static int s_common;
public:
static void getCommon () const { };
static void getCommon () { };
};
Now... how would you call the const
one? There's no const
object to call it on (well, you could call it on a const
object, but that's not the point).
I'm just guessing here, there probably are other reasons. :)
回答2:
However had it been allowed, the static member function's "const"ness could have been easily related to the static data members.
This is where your question becomes confused. A non-static member function declared as const
still has non-const
access to static data members. The const
only applies to this
(ie: the non-static data members).
It would make no sense for a static member function to use const
in the same way syntactically, yet have a completely different outcome (ie: making access to static data members const
).
Furthermore, static data members are nothing more than class-scoped global variables that have class access controls (public/private/etc) on them. So it doesn't make sense for some functions to have different const
access to them, especially based on their signature.
回答3:
The rationale for having const
cv-qualifier on member functions is:
To indicate that the hidden pointer this
being passed to the member function is immutable and it cannot be modified. A static
member function does not have the hidden this
parameter, and hence const
for static
member functions is meaningless.
However had it been allowed, the static member function's "const"ness could have been easily related to the static data members.
That was not the rationale for having const
qualifier to begin with, this is evident from the fact that you cannot have cv-qualifiers applied to a free function. The cv-qualifiers
were and are only meant for this
, the object whose function is being called.
回答4:
A function that doesn't change any global state is pure. C++11 introduces attributes that might include [[pure]]
on particular platforms.
One problem with const
is that it's part of the type of the function. Assigning that static const
function to a "normal" function pointer would require a special conversion, cast, or decay rule. And as Luchian mentions, it would allow completely ambiguous overloading.
Essentially you are describing forming a singleton object from the static
members, sharing a common, qualified indirect access path. For the non-const object to appear const, it must be accessed through something, but there's no this
. Would its decltype
change? There is no good answer. If you want all this, then put them explicitly inside a class
object.
回答5:
My guess is that using static
and const
on a member function to refer to constness of static member variables was simply never considered as an option. IMO your suggestion is kind of a strange (but maybe sensible) way of mixing those two keywords.
回答6:
Good question.
I believe conceptually const-ness applies to well-defined object or a data structure. Not to global/static or etc.
The same way I may ask why a global (or alternatively namespace-specific) function may not be const
, i.e. it may promise not to modify any global (or namespace-specific) variables.
This doesn't make too much sense IMHO. But yes, const-ness of static members belonging to a specific class - this might be useful in some cases IMHO.
来源:https://stackoverflow.com/questions/10100649/why-there-is-no-concept-of-const-correctness-for-classs-static-member-functio