问题
I have a little problem with my function. I would like to get all files in many directories. Currently, I can retrieve the files in the file passed in parameters. I would like to retrieve the html files of each folder in the folder passed as a parameter. I will explain if I put in parameter "test" I retrieve the files in "test" but I would like to retrieve "test / 1 / *. Html", "test / 2 / . /.html ":
var srcpath2 = path.join('.', 'diapo', result);
function getDirectories(srcpath2) {
return fs.readdirSync(srcpath2).filter(function (file) {
return fs.statSync(path.join(srcpath2, file)).isDirectory();
});
}
The result : [1,2,3]
thanks !
回答1:
It looks like the glob npm package would help you. Here is an example of how to use it:
File hierarchy:
test
├── one.html
└── test-nested
└── two.html
JS code:
var getDirectories = function (src, callback) {
glob(src + '/**/*', callback);
};
getDirectories('test', function (err, res) {
if (err) {
console.log('Error', err);
} else {
console.log(res);
}
});
which displays:
[ 'test/one.html',
'test/test-nested',
'test/test-nested/two.html' ]
回答2:
I needed to so something similar, in an Electron app: get all subfolders in a given base folder, using TypeScript, and came up with this:
import { readdirSync, statSync, existsSync } from "fs";
import * as path from "path";
// recursive synchronous "walk" through a folder structure, with the given base path
getAllSubFolders = (baseFolder, folderList = []) => {
let folders:string[] = readdirSync(baseFolder).filter(file => statSync(path.join(baseFolder, file)).isDirectory());
folders.forEach(folder => {
folderList.push(path.join(baseFolder,folder));
this.getAllSubFolders(path.join(baseFolder,folder), folderList);
});
}
回答3:
Here's mine. Like all good answers it's hard to understand:
const isDirectory = path => statSync(path).isDirectory();
const getDirectories = path =>
readdirSync(path).map(name => join(path, name)).filter(isDirectory);
const isFile = path => statSync(path).isFile();
const getFiles = path =>
readdirSync(path).map(name => join(path, name)).filter(isFile);
const getFilesRecursively = (path) => {
let dirs = getDirectories(path);
let files = dirs
.map(dir => getFilesRecursively(dir)) // go through each directory
.reduce((a,b) => a.concat(b), []); // map returns a 2d array (array of file arrays) so flatten
return files.concat(getFiles(path));
};
回答4:
const fs = require('fs');
const path = require('path');
var filesCollection = [];
const directoriesToSkip = ['bower_components', 'node_modules', 'www', 'platforms'];
function readDirectorySynchronously(directory) {
var currentDirectorypath = path.join(__dirname + directory);
var currentDirectory = fs.readdirSync(currentDirectorypath, 'utf8');
currentDirectory.forEach(file => {
var fileShouldBeSkipped = directoriesToSkip.indexOf(file) > -1;
var pathOfCurrentItem = path.join(__dirname + directory + '/' + file);
if (!fileShouldBeSkipped && fs.statSync(pathOfCurrentItem).isFile()) {
filesCollection.push(pathOfCurrentItem);
}
else if (!fileShouldBeSkipped) {
var directorypath = path.join(directory + '\\' + file);
readDirectorySynchronously(directorypath);
}
});
}
readDirectorySynchronously('');
This will fill filesCollection with all the files in the directory and its subdirectories (it's recursive). You have the option to skip some directory names in the directoriesToSkip array.
回答5:
You can also write your own code like below to traverse the directory as shown below :
var fs = require('fs');
function traverseDirectory(dirname, callback) {
var directory = [];
fs.readdir(dirname, function(err, list) {
dirname = fs.realpathSync(dirname);
if (err) {
return callback(err);
}
var listlength = list.length;
list.forEach(function(file) {
file = dirname + '\\' + file;
fs.stat(file, function(err, stat) {
directory.push(file);
if (stat && stat.isDirectory()) {
traverseDirectory(file, function(err, parsed) {
directory = directory.concat(parsed);
if (!--listlength) {
callback(null, directory);
}
});
} else {
if (!--listlength) {
callback(null, directory);
}
}
});
});
});
}
traverseDirectory(__dirname, function(err, result) {
if (err) {
console.log(err);
}
console.log(result);
});
You can check more information about it here : http://www.codingdefined.com/2014/09/how-to-navigate-through-directories-in.html
回答6:
I did mine with typescript works well fairly easy to understand
import * as fs from 'fs';
import * as path from 'path';
export const getAllSubFolders = (
baseFolder: string,
folderList: string[] = []
) => {
const folders: string[] = fs
.readdirSync(baseFolder)
.filter(file => fs.statSync(path.join(baseFolder, file)).isDirectory());
folders.forEach(folder => {
folderList.push(path.join(baseFolder, folder));
getAllSubFolders(path.join(baseFolder, folder), folderList);
});
return folderList;
};
export const getFilesInFolder = (rootPath: string) => {
return fs
.readdirSync(rootPath)
.filter(
filePath => !fs.statSync(path.join(rootPath, filePath)).isDirectory()
)
.map(filePath => path.normalize(path.join(rootPath, filePath)));
};
export const getFilesRecursively = (rootPath: string) => {
const subFolders: string[] = getAllSubFolders(rootPath);
const allFiles: string[][] = subFolders.map(folder =>
getFilesInFolder(folder)
);
return [].concat.apply([], allFiles);
};
来源:https://stackoverflow.com/questions/41462606/get-all-files-recursively-in-directories-nodejs