How can I receive OutputDebugString from a service?

问题

I'm trying to catch all OutputDebugString messages (including those from services) using the following code. It worked fine until I migrated to Windows 7.

The problem is that since Windows Vista services are running in the low level Session #0, some people say that it's impossible to catch them and some that it is. What do you think?

Is it possible to modify the following code by increasing some rights to be able to receive OutputDebugString messages from the Session #0? In other words; is it possible to share DBWIN_BUFFER in the session #0 with Session #1?

I would say it should be possible because e.g. DebugView can do that, and I can't see any service helper which would send those messages (e.g. through the named pipes) from the Session #0 to Session #1, where the GUI's running.

The problem will be IMO in the security settings. Can anyone suggest me how to modify them?

type
  TODSThread = class(TThread)
  protected
    procedure Execute; override;
  end;

...

procedure TODSThread.Execute;
var SharedMem: Pointer;
    SharedFile: THandle;
    WaitingResult: DWORD;
    SharedMessage: string;
    DataReadyEvent: THandle;
    BufferReadyEvent: THandle;
    SecurityAttributes: SECURITY_ATTRIBUTES;
    SecurityDescriptor: SECURITY_DESCRIPTOR;

begin
  SecurityAttributes.nLength := SizeOf(SECURITY_ATTRIBUTES);
  SecurityAttributes.bInheritHandle := True;
  SecurityAttributes.lpSecurityDescriptor := @SecurityDescriptor;

  if not InitializeSecurityDescriptor(@SecurityDescriptor, SECURITY_DESCRIPTOR_REVISION) then
    Exit;

  if not SetSecurityDescriptorDacl(@SecurityDescriptor, True, nil, False) then
    Exit;

  BufferReadyEvent := CreateEvent(@SecurityAttributes, False, True, 'DBWIN_BUFFER_READY');

  if BufferReadyEvent = 0 then
    Exit;

  DataReadyEvent := CreateEvent(@SecurityAttributes, False, False, 'DBWIN_DATA_READY');

  if DataReadyEvent = 0 then
    Exit;

  SharedFile := CreateFileMapping(THandle(-1), @SecurityAttributes, PAGE_READWRITE, 0, 4096, 'DBWIN_BUFFER');

  if SharedFile = 0 then
    Exit;

  SharedMem := MapViewOfFile(SharedFile, FILE_MAP_READ, 0, 0, 512);

  if not Assigned(SharedMem) then
    Exit;

  while (not Terminated) and (not Application.Terminated) do
    begin
      SetEvent(BufferReadyEvent);
      WaitingResult := WaitForSingleObject(DataReadyEvent, INFINITE);

      case WaitingResult of
        WAIT_TIMEOUT: Continue;
        WAIT_OBJECT_0:
          begin
            SharedMessage := String(PAnsiChar(SharedMem) + SizeOf(DWORD));
            // here I have what I need and process it in the main thread
          end;

       WAIT_FAILED: Continue;
     end;
   end;

   UnmapViewOfFile(SharedMem);
   CloseHandle(SharedFile);
end;

_{I've added the C# tag even if the code is in Delphi because the security attributes are common for the whole Windows API and C# has many followers :)}

回答1:

Someone talked about the same issue in the SysInternals forums. Their solution was to add "Global\" to the named objects.

So use the following

CreateEvent(@SecurityAttributes, False, True, 'Global\DBWIN_BUFFER_READY');
CreateEvent(@SecurityAttributes, False, False, 'Global\DBWIN_DATA_READY');
CreateFileMapping(THandle(-1), @SecurityAttributes, PAGE_READWRITE, 0, 4096, 'Global\DBWIN_BUFFER');

来源：https://stackoverflow.com/questions/6384785/how-can-i-receive-outputdebugstring-from-a-service

标签

Delphi

windows-services

remote-debugging

outputdebugstring