问题
When sleeping for a long time (like running time.sleep(3**3**3)
) in Python 3, the program returns an OverflowError with the error message "timestamp too large to convert to C _PyTime_t". What is the largest time length I can sleep?
回答1:
The value should be 9223372036.854775, which is "is the maximum value for a 64-bit signed integer in computing". See this Wikipedia article.
Mentioning of
_PyTime_t
in PEP 564:The CPython private "pytime" C API handling time now uses a new _PyTime_t type: simple 64-bit signed integer (C int64_t). The _PyTime_t unit is an implementation detail and not part of the API. The unit is currently 1 nanosecond.
>>> 2 ** 63 / 10 ** 9
9223372036.854776
>>> time.sleep(9223372036.854775)
^CTraceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyboardInterrupt
>>> time.sleep(9223372036.854776)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OverflowError: timestamp too large to convert to C _PyTime_t
>>>
回答2:
I found the following from the documentation of the threading library:
threading.TIMEOUT_MAX
The maximum value allowed for the timeout parameter of blocking functions (Lock.acquire(), RLock.acquire(), Condition.wait(), etc.). Specifying a timeout greater than this value will raise an OverflowError.
New in version 3.2.
On my system, with python 3.8:
>>> import threading
>>> threading.TIMEOUT_MAX
9223372036.0
I don't see it clearly specified anywhere that threading.TIMEOUT_MAX
is a maximum for the argument to time.sleep()
, but it appears to be the right value (or "close", for some reason), constructed with the same constraints.
来源:https://stackoverflow.com/questions/45704243/what-is-the-value-of-c-pytime-t-in-python