问题
Is it possible to get the logger wrapped by slf4j ?
For example, in debug mode, when I inspect org.slf4j.LoggerFactory.getLogger(loggerName)
, I can see the logger (here, java.util.logging
) :
I want to do something like :
// Get the real logger, cast in java.util.logging
java.util.logging.Logger myLogger = LoggerFactory.getLogger(loggerName))...;
// Use the java.util.logging methods
myLogger.setLevel(Level.parse(level));
回答1:
I've found a solution using reflection. Looking for the "logger" field in the slf4j Logger.
private <T> T getLogger(final String loggerName, final Class<T> loggerClass) {
final org.slf4j.Logger logger = LoggerFactory.getLogger(loggerName);
try {
final Class<? extends org.slf4j.Logger> loggerIntrospected = logger.getClass();
final Field fields[] = loggerIntrospected.getDeclaredFields();
for (int i = 0; i < fields.length; i++) {
final String fieldName = fields[i].getName();
if (fieldName.equals("logger")) {
fields[i].setAccessible(true);
return loggerClass.cast(fields[i].get(logger));
}
}
} catch (final Exception e) {
logger.error(e.getMessage());
}
return null;
}
Calling with:
java.util.logging.Logger myLogger = getLogger(loggerName, java.util.logging.Logger.class)
// or
org.apache.log4j.Logger myLogger = getLogger(loggerName, org.apache.log4j.Logger.class)
But maybe exists a better solution using the slf4j API ?
来源:https://stackoverflow.com/questions/21329953/how-to-get-the-logger-wrapped-in-slf4j