问题
Suppose I want to sample 10 times from multiple normal distributions with the same covariance matrix (identity) but different means, which are stored as rows of the following matrix:
means = np.array([[1, 5, 2],
[6, 2, 7],
[1, 8, 2]])
How can I do that in the most efficient way possible (i.e. avoiding loops)
I tried like this:
scipy.stats.multivariate_normal(means, np.eye(2)).rvs(10)
and
np.random.multivariate_normal(means, np.eye(2))
But they throw an error saying mean should be 1D.
Slow Example
import scipy
np.r_[[scipy.stats.multivariate_normal(means[i, :], np.eye(3)).rvs() for i in range(len(means))]]
回答1:
Your covariance matrix indicate that the sample are independent. You can just sample them at once:
num_samples = 10
flat_means = means.ravel()
# build block covariance matrix
cov = np.eye(3)
block_cov = np.kron(np.eye(3), cov)
out = np.random.multivariate_normal(flat_means, cov=block_cov, size=num_samples)
out = out.reshape((-1,) + means.shape)
来源:https://stackoverflow.com/questions/65252624/python-sample-from-multivariate-normal-with-n-means-and-same-covariance-matrix