How to print an exception?

问题

How to print python exception?

Example:

try:
    action()
except:
    print "Unexpected error:", sys.exc_info()[0]

Prints:

Unexpected error: <type 'exceptions.TypeError'>

It does not have much information for me.

回答1:

Use traceback module:

try:
    action()
except:
    import traceback
    traceback.print_exc()

回答2:

You can print the exception which occurred too.

try:
    action()
except exception as ex:
    print("Exception: " + str(ex))

来源：https://stackoverflow.com/questions/45131565/how-to-print-an-exception