问题
I have the following Exception while starting the spring context:
java.lang.Exception: java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.apache.catalina.LifecycleException: org.xml.sax.SAXParseException; systemId: http://www.springframework.org/schema/data/jpa/; lineNumber: 1; columnNumber: 55; White spaces are required between publicId and systemId.
Before I added the spring-data-jpa to the spring config.xml everything worked fine. Why isn't the xml not valid anymore?
spring config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd">
<context:property-placeholder location="classpath:application.properties" />
<context:component-scan base-package="com.example" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<!-- set up JPA and transaction config -->
<tx:annotation-driven transaction-manager="transactionManager" />
<!-- spring data jpa with JpaRepository -->
<jpa:repositories base-package="com.example.repositories" />
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driverClassName}" />
<property name="url" value="${jdbc.url}"/>
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}"/>
</bean>
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="${hibernate.show_sql:false}"/>
<property name="generateDdl" value="true"/>
<property name="database" value="MYSQL"/>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<!-- spring based scanning for entity classes-->
<property name="packagesToScan" value="com.example.entities"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" />
</beans>
回答1:
Please re-order the following lines:
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
..to this:
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
This is exactly where your error message points at, and the pair-wise appearance (namespace location
) is relevant!
来源:https://stackoverflow.com/questions/29884328/spring-config-xml-isnt-valid-after-adding-spring-data-jpa-schema-references