How do I convert an int to two bytes in C#?

问题

How do I convert an int to two bytes in C#?

回答1:

Assuming you just want the low bytes:

byte b0 = (byte)i,
     b1 = (byte)(i>>8);

However, since 'int' is 'Int32' that leaves 2 more bytes uncaptured.

回答2:

You can use BitConverter.GetBytes to get the bytes comprising an Int32. There will be 4 bytes in the result, however, not 2.

回答3:

Another way to do it, although not as slick as other methods:

Int32 i = 38633;
byte b0 = (byte)(i % 256);
byte b1 = (byte)(i / 256);

回答4:

Is it an int16?

Int16 i = 7;
byte[] ba = BitConverter.GetBytes(i);

This will only have two bytes in it.

回答5:

Option 1:

byte[] buffer = BitConverter.GetBytes(number);

Option 2:

byte[] buffer = new byte[2];

buffer[0] = (byte) number;
buffer[1] = (byte)(number >> 8);

I prefer option 1!

来源：https://stackoverflow.com/questions/3919804/how-do-i-convert-an-int-to-two-bytes-in-c