问题
can you guys help me to know how to connect a button in my PySimpleGui script which will execute another python script when the run button is pressed/clicked.
For now, i've been reading about Subprocess and command = os.popen in a GUI script.
layout = [[ sg.Text('Click the button to launch Program')],
[sg.Button('Launch')]]
win1 = sg.Window('My new window').Layout(layout)
win2_activate = False
while True:
ev1, vals1 = win1.Read()
if ev1 is None or ev1 == 'Cancel':
break
if not win2_activate and ev1 == 'Launch':
win1.Hide()
win2_activate = True
layout2 = [[sg.Text('Report Auto')],
[sg.Input(do_not_clear=True)],
[sg.Text('', key='_OUTPUT_')],
[sg.Button('Run'), sg.Button('Cancel')]]
win2 = sg.Window('Window2').Layout(layout2)
while True:
ev2, vals2 = win2.Read()
if ev2 is None or ev2 =='Cancel':
win2_activate = False
win2.Close()
win1.UnHide()
break
In my pysimplegui script, i have not yet included the subprocess or any library because i just don't know where to do it. Any help will is most welcome!
回答1:
Here's a full answer to your question, a PySimpleGUI program. This program allows you to type in a command. Then press a button. When button pressed the command is "run" and the output is shown in the window.
import subprocess
import sys
import PySimpleGUI as sg
def main():
layout = [ [sg.Text('Enter a command to execute (e.g. dir or ls)')],
[sg.Input(key='_IN_')], # input field where you'll type command
[sg.Output(size=(60,15))], # an output area where all print output will go
[sg.Button('Run'), sg.Button('Exit')] ] # a couple of buttons
window = sg.Window('Realtime Shell Command Output', layout)
while True: # Event Loop
event, values = window.Read()
if event in (None, 'Exit'): # checks if user wants to exit
break
if event == 'Run': # the two lines of code needed to get button and run command
runCommand(cmd=values['_IN_'], window=window)
window.Close()
# This function does the actual "running" of the command. Also watches for any output. If found output is printed
def runCommand(cmd, timeout=None, window=None):
p = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
output = ''
for line in p.stdout:
line = line.decode(errors='replace' if (sys.version_info) < (3, 5) else 'backslashreplace').rstrip()
output += line
print(line)
window.Refresh() if window else None # yes, a 1-line if, so shoot me
retval = p.wait(timeout)
return (retval, output) # also return the output just for fun
if __name__ == '__main__':
main()
回答2:
To make a button do something, all you need is to type:
if event in #<enter KEY here>:
#do your action
Replace the KEY with the key for the button (usually the name, in your case, 'Launch')
Then make a variable (e.g. LaunchWindow
) true, instead of calling the 'Launch' button from the other window. I don't think PySimpleGUI likes that...
来源:https://stackoverflow.com/questions/57200315/connect-process-a-script-to-pysimplegui-button