问题
I get a list of file paths from the backend, it represents a folder structure and looks like this:
paths = ["path/to/file1.doc", "path/to/file2.doc", "foo/bar.doc]
The lengths of the paths are arbitrary. In order to use a file tree component (angular2-tree-component) I need to transform this data into the following format:
nodes = [
{
"name": "path",
"children": [
{
"name": "to",
"children": [
{"name": "file1.doc"},
{"name": "file2.doc"}
]
}
]
},
{
"name": "foo",
"children": [
{"name": "bar.doc"}
]
}
]
I think the most efficient way to transform the data is to
- Map the array with the files mirroring a tree structure first and then to
- Iterate over every key in order to finalise the "children/parent" relations.
Step one:
transformToTree(data) {
const tree = {};
function addPathsToTree(paths) {
let map = tree
paths.forEach(function(item) {
map[item] = map[item] || {};
map = map[item];
});
}
data.forEach(function(path) {
let pathPart = path.split('/');
addPathsToTree(pathPart);
});
return pathTree;
}
When passing "nodes" into the transformToTree function (transformToTree(nodes)), I get the following result:
{
"path": {
"to": {
"file1.doc": {},
"file2.doc": {}
}
},
"foo": {
"bar": {}
}
}
I don't know how to proceed from here = how to iterate over all the keys and values while building the final array in the required structure.
There are a few examples like this or that on SO, but I was not able to understand how I could adapt them to my needs.
回答1:
I would go with two nested loops, one for pathes and one for the splitted names and find the name or create new objects.
var paths = ["path/to/file1.doc", "path/to/file2.doc", "foo/bar.doc"],
result = [];
paths.reduce((r, path) => {
path.split('/').reduce((o, name) => {
var temp = (o.children = o.children || []).find(q => q.name === name);
if (!temp) o.children.push(temp = { name });
return temp;
}, r);
return r;
}, { children: result });
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
来源:https://stackoverflow.com/questions/59049635/how-to-transform-array-of-strings-into-specific-tree-structure-in-javascript