问题
I'm trying to create bins (A_bin) within a DataFrame based on one column (A), and then create unique bins (B_bin) based on another column (B) within each of the original bins.
df = pd.DataFrame({'A': [4.5, 5.1, 5.9, 6.3, 6.7, 7.5, 7.9, 8.5, 8.9, 9.3, 9.9, 10.3, 10.9, 11.1, 11.3, 11.9],
'B': [3.2, 2.7, 2.2, 3.3, 2.1, 1.8, 1.4, 1.0, 1.8,2.4, 1.2, 0.8, 1.4, 0.6, 0, -0.4]})
df['A_bin'] = pd.cut(df['A'], bins=3)
df['B_bin'] = df.groupby('A_bin')['B'].transform(lambda x: pd.cut(x, bins=2))
This results in:
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-341-5742137b7574> in <module>()
2 'B': [3.2, 2.7, 2.2, 3.3, 2.1, 1.8, 1.4, 1.0, 1.8,2.4, 1.2, 0.8, 1.4, 0.6, 0, -0.4]})
3 df['A_bin'] = pd.cut(df['A'], bins=3)
----> 4 df['B_bin'] = df.groupby('A_bin')['B'].transform(lambda x: pd.cut(x, bins=2))
C:\Users\ddecker1\AppData\Local\Continuum\Anaconda3\lib\site-packages\pandas\core\groupby.py in transform(self, func, *args, **kwargs)
2761
2762 indexer = self._get_index(name)
-> 2763 result[indexer] = res
2764
2765 result = _possibly_downcast_to_dtype(result, dtype)
ValueError: could not convert string to float: '(2.0988, 2.7]'
It looks like it's trying to do the right thing, but I'm not sure why it's trying to change the the string to float.
回答1:
It's a kind of magic:
df.groupby('A_bin')[['B']].transform(lambda x: pd.cut(x, bins=2))
来源:https://stackoverflow.com/questions/42265471/applying-pandas-cut-within-a-groupby