How to groupBy object properties and map to another object using Java 8 Streams?

问题

Suppose I have a group of bumper cars, which have a size, a color and an identifier ("car code") on their sides.

class BumperCar {
    int size;
    String color;
    String carCode;
}

Now I need to map the bumper cars to a List of DistGroup objects, which each contains the properties size, color and a List of car codes.

class DistGroup {
    int size;
    Color color;
    List<String> carCodes;

    void addCarCodes(List<String> carCodes) {
        this.carCodes.addAll(carCodes);
    }
}

For example,

[
    BumperCar(size=3, color=yellow, carCode=Q4M),
    BumperCar(size=3, color=yellow, carCode=T5A),
    BumperCar(size=3, color=red, carCode=6NR)
]

should result in:

[
    DistGroup(size=3, color=yellow, carCodes=[ Q4M, T5A ]),
    DistGroup(size=3, color=red, carCodes=[ 6NR ])
]

I tried the following, which actually does what I want it to do. But the problem is that it materializes the immediate result (into a Map) and I also think that it can be done at once (perhaps using mapping or collectingAndThen or reducing or something), resulting in more elegant code.

List<BumperCar> bumperCars = ...
Map<SizeColorCombination, List<BumperCar>> map = bumperCars.stream()
    .collect(groupingBy(t -> new SizeColorCombination(t.getSize(), t.getColor())));

List<DistGroup> distGroups = map.entrySet().stream()
    .map(t -> {
        DistGroup d = new DistGroup(t.getKey().getSize(), t.getKey().getColor());
        d.addCarCodes(t.getValue().stream()
            .map(BumperCar::getCarCode)
            .collect(toList()));
        return d;
    })
    .collect(toList());

How can I get the desired result without using a variable for an immediate result?

Edit: How can I get the desired result without materializing the immediate result? I am merely looking for a way which does not materialize the immediate result, at least not on the surface. That means that I prefer not to use something like this:

something.stream()
    .collect(...) // Materializing
    .stream()
    .collect(...); // Materializing second time

Of course, if this is possible.

---

Note that I omitted getters and constructors for brevity. You may also assume that equals and hashCode methods are properly implemented. Also note that I'm using the SizeColorCombination which I use as group-by key. This class obviously contains the properties size and color. Classes like Tuple or Pair or any other class representing a combination of two arbitrary values may also be used.
Edit: Also note that an ol' skool for loop can be used instead of course, but that is not in the scope of this question.

回答1:

If we assume that DistGroup has hashCode/equals based on size and color, you could do it like this:

bumperCars
    .stream()
    .map(x -> {
        List<String> list = new ArrayList<>();
        list.add(x.getCarCode());
        return new SimpleEntry<>(x, list);
    })
    .map(x -> new DistGroup(x.getKey().getSize(), x.getKey().getColor(), x.getValue()))
    .collect(Collectors.toMap(
        Function.identity(),
        Function.identity(),
        (left, right) -> {
            left.getCarCodes().addAll(right.getCarCodes());
            return left;
        }))
    .values(); // Collection<DistGroup>

回答2:

Solution-1

Just merging the two steps into one:

List<DistGroup> distGroups = bumperCars.stream()
        .collect(Collectors.groupingBy(t -> new SizeColorCombination(t.getSize(), t.getColor())))
        .entrySet().stream()
        .map(t -> {
            DistGroup d = new DistGroup(t.getKey().getSize(), t.getKey().getColor());
            d.addCarCodes(t.getValue().stream().map(BumperCar::getCarCode).collect(Collectors.toList()));
            return d;
        })
        .collect(Collectors.toList());

Solution-2

Your intermediate variable would be much better if you could use groupingBy twice using both the attributes and map the values as List of codes, something like:

Map<Integer, Map<String, List<String>>> sizeGroupedData = bumperCars.stream()
        .collect(Collectors.groupingBy(BumperCar::getSize,
                Collectors.groupingBy(BumperCar::getColor,
                        Collectors.mapping(BumperCar::getCarCode, Collectors.toList()))));

and simply use forEach to add to the final list as:

List<DistGroup> distGroups = new ArrayList<>();
sizeGroupedData.forEach((size, colorGrouped) ->
        colorGrouped.forEach((color, carCodes) -> distGroups.add(new DistGroup(size, color, carCodes))));

Note: I've updated your constructor such that it accepts the card codes list.

DistGroup(int size, String color, List<String> carCodes) {
    this.size = size;
    this.color = color;
    addCarCodes(carCodes);
}

Further combining the second solution into one complete statement(though I would myself favor the forEach honestly):

List<DistGroup> distGroups = bumperCars.stream()
        .collect(Collectors.groupingBy(BumperCar::getSize,
                Collectors.groupingBy(BumperCar::getColor,
                        Collectors.mapping(BumperCar::getCarCode, Collectors.toList()))))
        .entrySet()
        .stream()
        .flatMap(a -> a.getValue().entrySet()
                .stream().map(b -> new DistGroup(a.getKey(), b.getKey(), b.getValue())))
        .collect(Collectors.toList());

回答3:

You can collect by by using BiConsumer that take (HashMap<SizeColorCombination, DistGroup> res, BumperCar bc) as parameters

Collection<DistGroup> values = bumperCars.stream()
        .collect(HashMap::new, (HashMap<SizeColorCombination, DistGroup> res, BumperCar bc) -> {
                SizeColorCombination dg = new SizeColorCombination(bc.color, bc.size);
                DistGroup distGroup = res.get(dg);
                if(distGroup != null) {
                    distGroup.addCarCode(bc.carCode);
                }else {
                    List<String> codes = new ArrayList();
                    distGroup = new DistGroup(bc.size, bc.color, codes);
                    res.put(dg, distGroup);
                }
                },HashMap::putAll).values();

回答4:

Check out my library AbacusUtil:

StreamEx.of(bumperCars)
         .groupBy(c -> Tuple.of(c.getSize(), c.getColor()), BumperCar::getCarCode)
         .map(e -> new DistGroup(e.getKey()._1, e.getKey()._2, e.getValue())
         .toList();

来源：https://stackoverflow.com/questions/54254064/how-to-groupby-object-properties-and-map-to-another-object-using-java-8-streams