问题
While this should be relatively straightforward, I can't figure out how to move (rather than copy) LI
elements between UL
s.
All I want is to drag any item from list foo to list bar (or vice versa) without duplicating the element.
While connectToSortable
does almost exactly what I want (though I'd prefer to avoid sortable
), it clones the element - and manually removing the original element by reacting to the stop
event turns out to be not so easy (e.g. ensuring that a valid drop actually happened).
A simple "hello world" example would help me greatly.
回答1:
A Hello World example can be found here: http://jqueryui.com/demos/sortable/#connect-lists. You don't need a draggable
at all, only a sortable
.
$(function() {
$("#sortable1, #sortable2").sortable({
connectWith: '.connectedSortable'
}).disableSelection();
});
If you want to disallow the sorting of items within one list, this may be a way to go. It's not the most beautiful UI though (the user is given false hope), and the user is also free to determine the drop position in a foreign list.
$(function() {
var sender;
var recvok = false;
$("#sortable1, #sortable2").sortable({
connectWith: '.connectedSortable',
start: function() {
sender = $(this);
recvok = false;
},
over: function() {
recvok = ($(this).not(sender).length != 0);
},
stop: function() {
if (!recvok)
$(this).sortable('cancel');
}
}).disableSelection();
});
This is a really horrible function working around what I feel is an incompleteness in jQuery UI. It saves the sender on sortstart and takes down a flag allowing drop. When another receiver is entered, it checks if it's not the sender and puts the flag up. On sortstop the flag is checked. Warning: this function is ugly to the eye of both the user and the programmer, but it works.
来源:https://stackoverflow.com/questions/3053201/jquery-ui-moving-items-from-one-list-to-another