WCF REST: What is it expecting my XML to look like in requests?

问题

I have the following method in my WCF service:

[OperationContract]
[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
    return 1;
}

I am sending xml from a Flex application, and it takes an object that looks like this: { param1: "test", param2: "test2" } and turns it into the following request:

POST http://localhost:8012/MyService.svc/GetOne HTTP/1.1
Accept: application/xml
Accept-Language: en-US
x-flash-version: 10,1,53,64
Content-Type: application/xml
Content-Length: 52
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; WOW64; Trident/5.0)
Host: localhost:8012
Connection: Keep-Alive
Pragma: no-cache
Cookie: ASP.NET_SessionId=drsynacw0ignepk4ya4pou23

<param1>something</param1><param2>something</param2>

I get the error The incoming message has an unexpected message format 'Raw'. The expected message formats for the operation are 'Xml', 'Json'.. Everything I've read indicates that I just need the content-type to be application/xml, but it still thinks it's Raw for some reason. Given my method signature, I'm confused as to what it's expecting and how I need to form the request so it will accept it as XML.

Am I missing something obvious here? Why does it think it's RAW when it's specifying XML and providing XML?

Edit - Here's the Flex side in case I'm missing something here.

var getOneService:HttpService = new HttpService("myURL");

getOneService.method = "POST";
getOneService.resultFormat = "e4x";
getOneService.contentType = HTTPService.CONTENT_TYPE_XML;
getOneService.headers = { Accept: "application/xml" };

getOneService.send({ param1: "test", param2: "test2" });

回答1:

I don't think you can pass 2 parameters with a POST operation for the framework to deserialize it automatically. You have try some of the below approaches:

Define your WCF method to be as below:

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.Bare, 
    ResponseFormat = WebMessageFormat.Xml, 
    RequestFormat = WebMessageFormat.Xml, 
    URITemplate="/GetOne/{param1}")]
public int GetOne(string param1, string param2)
{
    return 1;
}

Your raw POST request would looks like as below:

POST http://localhost/SampleService/RestService/ValidateUser/myparam1 HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 86

<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">my param2</string>

Change your WCF REST method to be as below:

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat = WebMessageFormat.Json, 
    RequestFormat = WebMessageFormat.Json)]
public int GetOne(string param1, string param2)
{
    return 1;
}

Now your raw request should looks something like below:

POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
User-Agent: Fiddler
Content-Type: application/json
Host: localhost
Content-Length: 86

{"param1":"my param1","param2":"my param 2"}

Change your WCF REST method to be as below:

[OperationContract]
[WebInvoke(Method="POST", 
    BodyStyle=WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat=WebMessageFormat.Xml, 
    RequestFormat= WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
   return 1;
}

Now your raw request would look like something below:

POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 116

<ValidateUser xmlns="http://tempuri.org/"><Username>my param1</Username><Password>myparam2</Password></ValidateUser>

回答2:

Valid XML must have a single root element. Also there's no magic in WCF REST that maps XML elements to string parameters. You could take an XElement as your operation parameter.

[OperationContract]
[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public int GetOne(XElement content)
{
    string param1 = content.Elements().First(element => element.Name == "param1").Value;
    string param2 = content.Elements().First(element => element.Name == "param2").Value;

    return 1;
}

The data you send would be something like:

<parameters>
    <param1>something</param1>
    <param2>something</param2>
</parameters>

来源：https://stackoverflow.com/questions/11439367/wcf-rest-what-is-it-expecting-my-xml-to-look-like-in-requests

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ASP.NET

wcf

apache-flex

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