Python - Convert seconds from epoch time into human readable time [duplicate]

问题

This question already has answers here:

In Python, how do you convert seconds since epoch to a `datetime` object? (5 answers)

Closed 6 years ago.

Originally I made this code to convert date into human readable time:

    a = datetime.datetime.strptime(time, "%Y-%m-%d %H:%M:%S.%f")
    b = datetime.datetime.now()
    c = b - a
    days, hours, minutes, seconds = int(c.days), int(c.seconds // 3600), int(c.seconds % 3600 / 60.0), int(c.seconds % 60.0)
    return days, hours, minutes, seconds
    EXAMPLE OUTPUT: 1 days, 4 hours, 24 minutes, 37 seconds

and I'm trying to make it using epoch time, but I have no idea on to make it calculate days hours and etc.

    a = last_epoch #last epoch recorded
    b = time.time() #current epoch time
    c = b - a #returns seconds
    hours = c // 3600 / 24 #the only thing I managed to figure out

回答1:

a = last_epoch #last epoch recorded
b = time.time() #current epoch time
c = b - a #returns seconds
days = c // 86400
hours = c // 3600 % 24
minutes = c // 60 % 60
seconds = c % 60

回答2:

import datetime
timestamp = 1339521878.04 
value = datetime.datetime.fromtimestamp(timestamp)
print(value.strftime('%Y-%m-%d %H:%M:%S'))

来源：https://stackoverflow.com/questions/26276906/python-convert-seconds-from-epoch-time-into-human-readable-time