remove leading 0s with stringr in R

问题

I have the following data

id
00001
00010
00022
07432

I would like to remove the leading 0s so the data would like like the following

id
1
10
22
7432

回答1:

Using the new str_remove function in stringr:

id = str_remove(id, "^0+")

回答2:

Here is a base R option using sub:

id <- sub("^0+", "", id)
id

[1] "1"    "10"   "22"   "7432"

Demo

回答3:

We can just convert to numeric

as.numeric(df1$id)
[#1]    1   10   22 7432

---

If we require a character class output, str_replace from stringr can be used

library(stringr)
str_replace(df1$id, "^0+" ,"")
#[1] "1"    "10"   "22"   "7432"

来源：https://stackoverflow.com/questions/49186893/remove-leading-0s-with-stringr-in-r