问题
AVX512 provide us with intrinsics to sum all cells in a __mm512 vector. However, some of their counterparts are missing: there is no _mm512_reduce_add_epi8, yet.
_mm512_reduce_add_ps //horizontal sum of 16 floats
_mm512_reduce_add_pd //horizontal sum of 8 doubles
_mm512_reduce_add_epi32 //horizontal sum of 16 32-bit integers
_mm512_reduce_add_epi64 //horizontal sum of 8 64-bit integers
Basically, I need to implement MAGIC in the following snippet.
__m512i all_ones = _mm512_set1_epi16(1);
short sum_of_ones = MAGIC(all_ones);
/* now sum_of_ones contains 32, the sum of 32 ones. */
The most obvious way would be using _mm512_storeu_epi8 and sum the elements of the array together, but that would be slow, plus it might invalidate the cache. I suppose there exists a faster approach.
Bonus points for implementing _mm512_reduce_add_epi16 as well.
回答1:
First of all, _mm512_reduce_add_epi64 does not correspond to a single AVX512 instruction, but it generates a sequence of shuffles and additions.
To reduce 64 epu8 values to 8 epi64 values one usually uses the vpsadbw instruction (SAD=Sum of Absolute Differences) against a zero vector, which then can be reduced further:
long reduce_add_epu8(__m512i a)
{
return _mm512_reduce_add_epi64(_mm512_sad_epu8(a, _mm512_setzero_si512()));
}
Try it on godbolt: https://godbolt.org/z/1rMiPH. Unfortunately, neither GCC nor Clang seem to be able to optimize away the function if it is used with _mm512_set1_epi16(1).
For epi8 instead of epu8 you need to first add 128 to each element (or xor with 0x80), then reduce it using vpsadbw and at the end subtract 64*128 (or 8*128 on each intermediate 64bit result). [Note this was wrong in a previous version of this answer]
For epi16 I suggest having a look at what instructions _mm512_reduce_add_epi32 and _mm512_reduce_add_epi64 generate and derive from there what to do.
Overall, as @Mysticial suggested, it depends on your context what the best approach of reducing is. E.g., if you have a very large array of int64 and want a sum as int64, you should just add them together packet-wise and only at the very end reduce one packet to a single int64.
来源：https://stackoverflow.com/questions/55296777/summing-8-bit-integers-in-m512i-with-avx-intrinsics