BASH: How to find no. of days (considering only “Network / Business Days”) between two dates (i.e. exclude weekends Saturday/Sunday)

问题

RHEL 7.5

BASH GNU bash, version 4.2.46(2)-release (x86_64-redhat-linux-gnu)

In MS Excel, I'm able to use Network days to find no. of days between two dates. Wondering if it's possible using bash as first preference (--or any other pre-installed language on Linux supporting to solve this possibly using a one-liner - my second preference). I'm not sure if there exists any library or custom tool/utility in Linux which calculates this value.

To calculate the number of workdays between two dates, you can use the NETWORKDAYS function. NETWORKDAYS automatically excludes weekends, and it can optionally exclude a custom list of holidays as well. Note that NETWORKDAYS includes both the start and end dates in the calculation if they are workdays.

I have a file.txt containing 2 column fields in YYYY-mm-dd format for Resolved and Start dates (you can ignore header line for now):

Resolved,StartOfWork
2020-01-16,2020-01-10
2020-01-13,2020-01-13
2020-01-20,2020-01-15
2020-01-20,2020-01-14
2020-01-14,2020-01-09
2020-01-09,2020-01-08
2020-01-16,2020-01-14
2020-01-09,2020-01-07
2020-01-14,2020-01-12

For each row, I want to calculate no. of NETWORK i.e. WEEK DAYS only between these 2 dates (doesn't matter if Resolved/StartOfWork dates were on weekend days: Saturday/Sunday).

The calculation of no. of days SHOULD NOT include 'weekend-days i.e. Saturday/Sunday in it.

PS: For the purpose of this post, my question is very different than what this post is asking for: How to find the difference in days between two dates?

回答1:

It may be the reinvention of the wheel but here's a bash solution (if interested).
Note that it requires the -d option to the date command.

while IFS="," read -r endday startday; do
    if (( lineno++ == 0 )); then                # handle header line
        echo "Resolved,StartOfWork,TotalDates"
        continue
    fi
    startsec=$(date -d "$startday" +%s)
    startdayofweek=$(date -d "$startday" +%w)   # 0 for Sun, ... 6 for Sat
    endsec=$(date -d "$endday" +%s)
    days=$(( (endsec - startsec) / 86400 + 1 )) # calendar days
    weeks=$(( days / 7 ))                       # number of weeks
    frac=$(( days % 7 ))                        # fraction mod 7
    if (( startdayofweek == 0 )); then          # case of starting on Sunday
        if (( frac > 0 )); then
            add=1                               # additional number of holidays
        else
            add=0
        fi
    else
        magic=$(( frac + (startdayofweek + 6) % 7 ))
                                                # calculate number of holidays
                                                # in the fraction period
        if (( magic < 6 )); then
            add=0
        elif (( magic == 6 )); then
            add=1
        else
            add=2
        fi
    fi
    holidays=$(( weeks * 2 + add ))             # total number of holidays
    workdays=$(( days - holidays ))             # subtract the holidays
    echo "$endday,$startday,$workdays"
done < inputfile

回答2:

I'd call through to a Python interpreter for this. Adopting the accepted answer from Using Python to count the number of business days in a month? --

countBusinessDaysPy=$(cat <<'EOF'
import datetime, sys

businessdays = 0
startDate = datetime.date.fromisoformat(sys.argv[1])
endDate = datetime.date.fromisoformat(sys.argv[2])
if endDate < startDate:
    (startDate, endDate) = (endDate, startDate)

while startDate <= endDate:      # change from <= to < to not count both start and end days
    if startDate.weekday() < 5:
        businessdays += 1
    startDate += datetime.timedelta(days=1)

print(businessdays)
EOF
)

countBusinessDays() { python3 -c "$countBusinessDaysPy" "$@"; }

...gives you a shell function that calls a Python interpreter to do the math you need (note that this is an inclusive range). Thereafter:

$ countBusinessDays 2019-01-01 2020-01-01
262
$ countBusinessDays 2019-01-01 2019-01-07
5

Calling this looping over your file (note that in the real world, I'd do the looping in Python, not in bash) might look like:

{
  read -r header; printf '%s\n' "$header,TotalDates"
  while IFS=, read -r resolved startOfWork rest; do
    printf '%s\n' "${resolved},${startOfWork}${rest:+,$rest},$(countBusinessDays "$startOfWork" "$resolved")"
  done
} <yourInputFile

...which emits as output:

Resolved,StartOfWork,TotalDates
2020-01-16,2020-01-10,5
2020-01-13,2020-01-13,1
2020-01-20,2020-01-15,4
2020-01-20,2020-01-14,5
2020-01-14,2020-01-09,4
2020-01-09,2020-01-08,2
2020-01-16,2020-01-14,3
2020-01-09,2020-01-07,3
2020-01-14,2020-01-12,2

来源：https://stackoverflow.com/questions/60218439/bash-how-to-find-no-of-days-considering-only-network-business-days-betwe

标签

Linux

bash

shell

date