Use Reflection to call generic method on object instance with signature: SomeObject.SomeGenericInstanceMethod<T>(T argument)

天大地大妈咪最大 提交于 2019-11-28 02:10:51

You do it exactly the same way.

When you call MethodInfo.Invoke, you pass all the arguments in an object[] anyway, so it's not like you have to know the types at compile time.

Sample:

using System;
using System.Reflection;

class Test
{
    public static void Foo<T>(T item)
    {
        Console.WriteLine("{0}: {1}", typeof(T), item);
    }

    static void CallByReflection(string name, Type typeArg,
                                 object value)
    {
        // Just for simplicity, assume it's public etc
        MethodInfo method = typeof(Test).GetMethod(name);
        MethodInfo generic = method.MakeGenericMethod(typeArg);
        generic.Invoke(null, new object[] { value });
    }

    static void Main()
    {
        CallByReflection("Foo", typeof(object), "actually a string");
        CallByReflection("Foo", typeof(string), "still a string");
        // This would throw an exception
        // CallByReflection("Foo", typeof(int), "oops");
    }
}

You do it exactly the same way, but pass an instance of your object:

typeof (SomeObject).GetMethod(
       "SomeGenericInstanceMethod", 
        yourObject.GetType())  
                 // Or typeof(TheClass), 
                 // or typeof(T) if you're in a generic method
   .MakeGenericMethod(typeof(GenericParameter))

The MakeGenericMethod method only requires you to specify the generic type parameters, not the method's arguments.

You'd pass the arguments in later, when you call the method. However, at this point, they're passing as object, so it again doesn't matter.

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