json data into php variables

问题

I have to parse this json data using PHP and store the values into PHP variables.

{  
"sender": "am@email.com",  
"receiver": "ak@email.com",  
"msg_id": "msg1_am@email.com",   
"subject": "Group Discussion",   
"references": ["msg1_aman@email.com","msg1_s@email.com","msg1_v@email.com"]
}

I am using this PHP code, its not working; pls check it.

For the fields 'sender', 'receiver', 'msg_id'and 'subject, I am using PHP variables '$msg_id', '$sender', '$receiver' and '$subject'.
I am trying to store the data of 'references' in the array 'ref_id'.

Also, the file 'dataset_f.json' has content in the following way:

{ "sender":"aman@email.com","receiver":"akash@email.com","msg_id":"msg1_aman@email.com","subject": "Project Discussion","references":["msg1_aman@email.com","msg1_s@email.com","msg1_v@email.com"]}

{ "sender":"akash@email.com","receiver":"aman@email.com","msg_id":"msg1_akash@email.com","subject": "Project Discussion","references":["msg1_aman@email.com","msg1_s@email.com","msg1_v@email.com"]}

Thats why the php code is reading the file line by line

<?php
$h1 = fopen("dataset_f.json", "r");
while(!feof($h1)){
$line = fgets($h1);
$test_case = json_decode($line);

$ref_id = array();
$msg_id = $test_case->{'msg_id'};
$sender = $test_case->{'sender'};
$receiver = $test_case->{'receiver'};
$subject = $test_case->{'subject'};
foreach($test_case as $val)
 {
    foreach($val -> references as $refer)
    {
        array_push($ref_id, $refer->ref);
    }
 }

// printing the values
$arrlen=count($ref_id);
 for($x=0;$x<$arrlen;$x++)
 { echo $ref_id[$x]." "; }
echo $msg_id." ".$sender." ".$receiver." ".$subject." <br> ";

}
?>

回答1:

Store the whole file as a string, decode it and store the values in you variables. Show the json your using. your using the -> incorrect, thats for objects not arrays, json_decode() returns an associative array if the next param is true. ref_id will hold a string thats comma separated.

dataset_f.json

{
    "sender":"am@email.com",
    "receiver":"ak@email.com",
    "msg_id":"msg1_am@email.com",
    "subject":"Group Discussion",
    "references":["msg1_aman@email.com","msg1_s@email.com","msg1_v@email.com"]
}

php code

$json = file_get_contents("dataset_f.json");

$data = json_decode($json, true);

// here depends on the json

$ref_id = ( ( is_array( $data["references"] ) ? implode(", ", $data["references"]) : $data["references"] ) ); // array to string
$msg_id = $data["msg_id"];
$sender = $data["sender"];
$receiver = $data["receiver"];
$subject = $data["subject"];

来源：https://stackoverflow.com/questions/23601180/json-data-into-php-variables

标签

php

json

parsing