问题
I am using Ansible 2.3.0.0 and I have tested in Ansible 2.4.0.0, obtaining the same result. My problem is simple. I have the following list:
vars:
password_text_to_encrypt:
- { line: "{{truststore_pass }}" , result: }
- { line: "{{ keystore_pass }}" , result: }
- { line: "{{ gp_pass }}" , result: }
- { line: "{{ datasource_password }}" , result: }
- { line: "{{ server_password }}" , result: }
- { line: "{{ sftp_password }}" , result: }
- { line: "{{ db_userpassword }}" , result: }
roles:
- basic_role
I want to encrypt the line value for every item of the list and save it in its results attribute. I am trying with this Ansible code but it fails in the task assignation:
- name: "Encrypt password"
uri:
url: http://122.81.10.1:8910/Cloud/encrypt
method: POST
body: "{{ item.line}}"
return_content: yes
register: "r"
with_items:
- "{{password_text_to_encrypt}}"
- name: "Replace var in result"
set_fact: item['0']['result']="{{ item.1.content}}"
#replace: '{{ item.1.content}}'
with_nested:
- "{{password_text_to_encrypt}}"
- "{{r.results}}"
when: item.1.item.line==item.0.line
- name: "print Results"
debug:
msg: "The Item is :{{item.result}}"
with_items:
- "{{password_text_to_encrypt}}"
The output message is:
"msg": "The variable name 'item['0']['result']' is not valid. Variables must start with a letter or underscore character, and contain only letters, numbers and underscores."}
I have tested with other possibilities but I do not achieve that every item.results save its encrypted value
回答1:
Finally, the set_fact method must be used in this way:
Instead of using the same variable, I have created another one with the same structure.
- name: "Replace var in result"
set_fact:
encrypted: "{{encrypted|default([]) + [ {'line': item.1.content, 'regexp': item.0.regexp} ]}}"
with_nested:
- "{{password_text_to_encrypt}}"
- "{{r.results}}"
when: item.1.item.line==item.0.line
But I cannot rewrite a field inside a object
来源:https://stackoverflow.com/questions/47882281/ansible-how-to-modify-a-variable-during-a-loop