问题
Does Boost Hana provide a way to combine predicates with logical operators?
I'm referring to something roughly like this
constexpr auto both = [](auto&& f, auto&& g){
return [&f,&g](auto&& x){ return f(x) && g(x); };
};
that could be used like this:
int main() {
std::vector<int> v{1,2,3,4,5,6,7,8,9,10};
auto less_than_7 = hana::reverse_partial(std::less_equal<int>{}, 7);
auto more_than_3 = hana::reverse_partial(std::greater_equal<int>{}, 3);
auto r = ranges::views::remove_if(v, both(less_than_7, more_than_3));
}
where, from Hana, I'd expect also a way to use it in an infix way similar to hana::on, as in both(less_than_7, more_than_3) === less_than_7 ^both^ more_than_3
(even though and
would be nicer, but I've just found that it's a synonym for &&
).
Or maybe does it offer a way to lift the standard operator &&
to operate on function functors?
回答1:
You could use demux like:
auto both = hana::demux(std::logical_and<bool>{});
// Or for any number of predicates
auto all = hana::demux([](auto const&... x) noexcept(noexcept((static_cast<bool>(x), ...))) { return (true && ... && static_cast<bool>(x)); });
ranges::views::remove_if(v, both(less_than_7, more_than_3));
来源:https://stackoverflow.com/questions/64259413/combining-predicates-in-a-functional-way